Answer:
<u>The equation can be y = 3b/5 or b = 5y/3</u>
Correct statement and question:
The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of special green paint for his costume.
Write an equation that relates the amounts (in liters) of yellow paint (y) and blue paint (b) needed to make the Green Goober's special green paint.
Source:
Previous question that can be found at brainly
Step-by-step explanation:
Let y to be the amount of liters of yellow paint needed to make the Green Goober's special green paint.
Let b to be the amount of liters of blue paint needed to make the Green Goober's special green paint.
We know that:
y:b = 3:5
Therefore,
5y = 3b, dividing by 5 at both sides we have:
y = 3b/5
And also dividing by 3 at both sides we have:
<u>b = 5y/3</u>
Both equations relate the amounts (in liters) of yellow paint and blue paint needed to make the Green Goober's special green paint.
Answer:
See the explanation
Step-by-step explanation:
(a)
H0: Consultant with more experience has the higher population mean service rating.
H1: Consultant with more experience doesn't have the higher population mean service rating.
(b)
t = 1.9923 (see the attached image)
(c)
The degrees of freedom for the test statistic,
df = 16
The P-value of the one tailed t- test with 16 degrees of freedom is,
P−value = tdist(X,df,tails)
P-value = tdist(1.9923,16,1)
P-value = 0.032
(d)
Since, P-value 0.032 is less than the significance level 0.05, there is an enough evidence to reject the null hypothesis.
Hence, there is a sufficient evidence to conclude that Consultant with more experience doesn't have the higher population mean service rating.
Hope this helps!
Step-by-step explanation:
466666666667/100000000000
Answer:
1) ΔCBF ≅ ΔCDF by (SSS)
2) ΔBFA ≅ ΔDFE by (SAS)
3) ΔCBE ≅ ΔCDA by (HL)
Step-by-step explanation:
1) Since BC ≅ DC and DF ≅ BF where CF ≅ CF (reflective property) we have;
ΔCBF ≅ ΔCDF by Side Side Side (SSS) rule of congruency
2) Since DF ≅ BF and FA ≅ FE where ∠DFE = ∠BFA (alternate angles)
Therefore;
ΔBFA ≅ ΔDFE by Side Angle Side (SAS) rule of congruency
3) Since FA ≅ FE and DF ≅ BF then where EB = FE + BF and AD = FA + DF
Where:
EB and AD are the hypotenuse sides of ΔCBE and ΔCDA respectively
We have that;
EB = AD from FE + BF = FA + DF
Where we also have BC ≅ DC
Where:
BC and DC are the legs of ΔCBE and ΔCDA respectively
Then we have the following relation;
ΔCBE ≅ ΔCDA by Hypotenuse Leg (HL).
<span>1. Quizzes (10% each):
60 x 10/100 = 6
69 x 10/100 = 6.9
68 x 10/100 = 6.8
2. Exam (70%)
65 x 70/100 = 45.5
Add them all up now:
6 + 6.9 + 6.8 + 45.5 = 65.2
Therefore, answer is </span><span>65.2</span>