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2 years ago

good job on increasing our team sales from 90 to 130 units per day.” wow i never thought that we could increase our sales by

Mathematics

1 answer:

artcher [175]2 years ago

7 0

The sales was increased by 44.4%.

Step-by-step explanation:

Lets do this cumulative
90 of 10 % = 9 which is 99
90 of 10 % = 9 which is 108
90 of 10% = 9 which is 117
90 of 10% = 9 which is 126
90 of 4 % = 3.6 which is 129.6
90 of 0.044% = 0.0396 which is 129.99
This comes to nearly 44.44 to be closer there was an increase.
Always rule 1 approximation use 50% of 90 if it is above 130.
Down it to 40% of 90 see if the sales is lower than 130.
It should always start with 50,40,30....10 percents.
Alternative should be 10,1 or decimals.
Approximation using decimals rounding up becomes simple.

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A 15-inch candle is lit and steadily burns until it is burned out. Let b represent the burned length of the candle (in inches) a

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Answer:

(a)r=15-b

11.9 Inches

(b)See attached

Step-by-step explanation:

Length of the candle =15 inch

Let b represent the burned length of the candle (in inches)

Let r represent the remaining length of the candle (in inches).

Therefore:

(a) r+b=15

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When b=3,1 Inches

Remaining Length, r=15-3.1=11.9 Inches

(b)The graph showing te relationship between r and b is shown below.

r is plotted on the y-axis while b is plotted on the x-axis as labelled.

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2 years ago

an art teacher uses 1 quart of blue paint each month.in one year,how many gallons of paint will she use

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Jack is flying his kite . He runs 100 feet away from his house and lets out 45 feet of string . The angle of elevation from the

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Answer: 125.80 ft

Step-by-step explanation:

Asuming the described situation is as shown in the figure below, we need to find the distance $h$ between the kite and Jacks house, but first we need to find the $x$ , $y$ and then $d$ .

How?

We will use trigonometry, especifically the trigonometric functions sine and cosine:

For $y$ :

$sin(65 \°)=\frac{y}{45 ft}$ (1)

Where $y$ is the opposite side to the angle and $45 ft$ the hypotenuse.

Isolating $y$ :

$y=40.78 ft$ (2)

For $x$ :

$cos(65 \°)=\frac{x}{45 ft}$ (3)

Where $x$ is the adjacent side to the angle.

Isolating $x$ :

$y=19.017 ft$ (4)

Finding $d$ :

$d=x+100 ft$ (5)

$d=19.017 ft +100 ft$

$d=119.017 ft$ (6)

Now that we have found these values, we have to work with a bigger triangle, where the hypotenuse is the distance between the kite and Jack's house $h$ and the sides are the values calculated in (4) and (6).

So, in this case we will use the <u>Pithagorean theorem</u>:

$h^{2}=y^{2} +d^{2}$ (7)

Isolating $h$ and writing with the known values:

$h=\sqrt{y^{2} +d^{2}}$ (8)

$h=\sqrt{(19.017 ft)^{2} +(119.017 ft)^{2}}$ (9)

$h=125.80 ft$ This is the distance between the kite and the house

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