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dem82 [27]
2 years ago
11

amit works out at a gym for three quarters of an hours.he uses the treadmill for half the total workout session time and one thi

rd on cycle.find the total time he spend on other miscellaneous exercises.
Mathematics
2 answers:
Nostrana [21]2 years ago
7 0

Answer:

Amit spends 7.5 minutes on other miscellaneous exercises.

Step-by-step explanation:

Amit works out at a gym for three quarters of an hours.

Three quarter of an hour means \frac{3}{4}\times60 =45 minutes

He uses the treadmill for half the total workout session time, means for \frac{45}{2}= 22.5 minutes

He uses one third time on cycle means \frac{1}{3}\times45=15 minutes

Now, time spent on miscellaneous exercises = 45-(22.5+15)=7.5 minutes

Therefore, total time Amit spends on other miscellaneous exercises is 7.5 minutes.

Kryger [21]2 years ago
6 0
Three quarter of an hour equals 45 minutes, he spends half of it on treadmill I.e 22.5 minutes, and one third I.e 15 minutes on cycle, hence the remains time should give the time he spent on other exercises which is 45-22.5-15=7.5 minutes i.e. One eight of an hour
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Answer:

Mean and standard deviation of the sampling distribution of the sample proportions are 76 and 0.0427 respectively.

Step-by-step explanation:

The mean for a sample proportion is given by μ = np

n = sample size = 100

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μ = 0.76 × 100 = 76.

Standard deviation of a sample proportion = σ = √[p(1-p)/n] = √(0.76×0.24/100) = 0.0427

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At a pond there were 24 ducks swimming. The ratio of ducklings to adult ducks is 5:1. How many ducklings were swimming at the po
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Twenty ducklings were swimming at the pond
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Dawn raises money for her school in a jog-a-thon. She will get three dollars for every lap she completes. If it takes 4 laps to
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The probability that a call received by a certain switchboard will be a wrong number is 0.02. Use the Poisson distribution to ap
MAXImum [283]

Answer:

0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

The probability that a call received by a certain switchboard will be a wrong number is 0.02.

150 calls. So:

\mu = 150*0.02 = 3

Use the Poisson distribution to approximate the probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Either there are less than two calls from wrong numbers, or there are at least two calls from wrong numbers. The sum of the probabilities of these events is 1. So

P(X < 2) + P(X \geq 2) = 1

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P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

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P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1992 = 0.2008

0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

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kozerog [31]
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