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Genrish500 [490]
1 year ago
13

The revenue each season from tickets at the theme part is represented by t(x) = 5x. The cost to pay the employees each season is

represented by r(x) = (1.5)x. Examine the graph of the combined function for total profit and estimate the profit after four seasons.
A. 1

B. 5

C. 10

D. 15

Mathematics
1 answer:
Over [174]1 year ago
8 0

Answer:  D. 15

Step-by-step explanation:

Given : The revenue each season from tickets at the theme part is represented by t(x) = 5x .

The cost to pay the employees each season is represented by r(x) = (1.5)x.

From the given graph , we can see that at 4th season, the profit = 15

Hence, the estimated profit after four seasons. =15

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NEED HELP FAST WILL GIVE BRAINIEST
vladimir1956 [14]

Answer:

x^2 + 8x - 65 = 0.

Step-by-step explanation:

In order to solve the side of the enlarged area of 81 square inches, we use the equation in solving the area of a square. Area = side^2.

the increase in side will be x, so (4+x)^2 = 81, x^2 + 4x + 4x + 16 = 81

x^2 + 8x + 16 - 81 = 0

x^2 + 8x - 65 = 0.

  Hoped this helped mark Brainliest!

5 0
1 year ago
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A rectangular prism is shown below 15mm 10mm 9mm
Verdich [7]
Area of cross section x height
Hope this helps
6 0
2 years ago
Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the stu
True [87]

Answer:

The fraction of the students who failed to went partying = \frac{1}{10}

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = \frac{20}{100} × 100

⇒ No. of students partied before the exam =  20

No. of students who not partied before the exam = \frac{20}{2} = 10

Thus the fraction of the students who failed to went partying = \frac{10}{100} = \frac{1}{10}

8 0
2 years ago
What is the difference of the polynomials?(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)A–6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5B–6x4y 
saul85 [17]

We have to calculate the difference of the given polynomials, we follows as:

(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-(6x^{4}y-5x^{2}y^{3}-y^{5})

After opening the brackets, the signs of all the terms changes as there is negative sign before the bracket.

=(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-6x^{4}y+5x^{2}y^{3}+y^{5})

Combining all the like terms, we get as

=(-2x^{3}y^{2})+(4x^{2}y^{3}+5x^{2}y^{3})-3xy^{4}-6x^{4}y+y^{5}

=-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^{5}

Option A is the correct answer.

6 0
1 year ago
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What is the final amount if 784 is decreased by 1% followed by a 4% increase?
Iteru [2.4K]

Answer:

The final amount  if 784 is decreased by 1% followed by a 4% increase is 807.52.

Step-by-step explanation:

General Formula

<em>A way to solve this problem is as follows</em>:

The general formula for this is taking into account that:

\\ percent\;change = \frac{change}{starting\;point}

The <em>starting point</em> is number 784.

The most important key is the solution for this answer is that:

\\ change = starting\;point - x

Where <em>x</em> is a number that we need to find. Then

\\ percent\;change = \frac{starting\;point - x}{starting\;point} [1]

Is 784 increased or decreased after all?

We also need to evaluate the following: if a quantity decreases a percentage, and then increases in another percentage, what is the final percentage? In this case, we have first that 784 decreases by 1% and then increases by 4%. As a result 784 will +4% - 1% = +3%, that is, 784 will increase in 3%.

Finding the result

If 784 increases by 3%, we have:

\\ 3\% = \frac{784 - x}{784}

Which is equal to

\\ 0.03 = \frac{784 - x}{784}

Solving for <em>x</em>, we first multiply by 784 to both sides of the previous formula:

\\ 0.03 * 784 = \frac{784 - x}{784}*784

\\ 0.03 * 784 = (784 - x)*\frac{784}{784}

\\ 0.03 * 784 = (784 - x)*1

\\ 0.03 * 784 = (784 - x)

Remember that if we add, subtract, multiply, divide... to both sides of the equation, we do not "alter" this equation.

Subtracting 784 to both sides:

\\ (0.03 * 784) - 784 = (784 - 784 - x)

\\ (0.03 * 784) - 784 = (0 - x)

\\ (0.03 * 784) - 784 = - x

\\ 23.52 - 784 = - x

\\ -760.48 = - x

Multiplying by -1 to both sides:

\\ -1 * (-760.48) = -1 * (-x)

We have to remember that:

\\ +*+ = +; - * - = +; - * + = -; + * - = -

\\ 760.48 = x

Then

\\ x = 760.48

Therefore, using formula [1], an increase of 3% is

\\ 3\% = \frac{784 - 760.48}{784}

\\ change = 784 - 760.48

\\ change = 23.52

Since an increase of 3% is 23.52, we have to add this to the starting point 784, and finally the amount is 784 + 23.52 = 807.52.

As a result, the final amount if 784 is decreased by 1% followed by a 4% increase is 807.52.  

In a more <em>terse way</em> of solving this problem, we can say that:

Increase of 4% = 784 * 0.04 = 31.36.

Decrease of 1% = 784 * 0.01 = 7.84.

Difference = 31.36 - 7.84 = 23.52.

Then, we need to add this value to 784, and 784 + 23.52 = 807.52 (the same result).

5 0
1 year ago
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