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Mrac [35]
1 year ago
9

In politics, marketing, etc. We often want to estimate a percentage or proportion p. One calculation in statistical polling is t

he margin of error - the largest (reasonble) error that the poll could have. For example, a poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% (72% minus 4% to 72% plus 4%). In a (made-up) poll, the proportion of people who like dark chocolate more than milk chocolate was 32% with a margin of error of 2.2%. Describe the conclusion about p using an absolute value inequality.
Mathematics
1 answer:
inessss [21]1 year ago
6 0

Answer: |p-72% |≤ 4%

Step-by-step explanation:

Let p be the population proportion.

The absolute inequality about p using an absolute value inequality.:

|p-\hat{p}| \leq E , where E = margin of error, \hat{p} = sample proportion

Given:  A poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% .

|p-72% |≤ 4%

⇒    72% - 4% ≤ p ≤ 72% +4%

⇒  68%  ≤ p ≤  76%.

i.e. p is most likely to be between 68% and 76% (.

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Find c1 and c2 such that M2+c1M+c2I2=0, where I2 is the identity 2×2 matrix and 0 is the zero matrix of appropriate dimension.
Katyanochek1 [597]

The question is missing parts. Here is the complete question.

Let M = \left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]. Find c_{1} and c_{2} such that M^{2}+c_{1}M+c_{2}I_{2}=0, where I_{2} is the identity 2x2 matrix and 0 is the zero matrix of appropriate dimension.

Answer: c_{1} = \frac{-16}{10}

             c_{2}=\frac{-214}{10}

Step-by-step explanation: Identity matrix is a sqaure matrix that has 1's along the main diagonal and 0 everywhere else. So, a 2x2 identity matrix is:

\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

M^{2} = \left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right]

M^{2}=\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]

Solving equation:

\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+c_{1}\left[\begin{array}{cc}6&5\\-1&-4\end{array}\right] +c_{2}\left[\begin{array}{cc}1&0\\0&1\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]

Multiplying a matrix and a scalar results in all the terms of the matrix multiplied by the scalar. You can only add matrices of the same dimensions.

So, the equation is:

\left[\begin{array}{cc}31&10\\-2&15\end{array}\right]+\left[\begin{array}{cc}6c_{1}&5c_{1}\\-1c_{1}&-4c_{1}\end{array}\right] +\left[\begin{array}{cc}c_{2}&0\\0&c_{2}\end{array}\right] =\left[\begin{array}{cc}0&0\\0&0\end{array}\right]

And the system of equations is:

6c_{1}+c_{2} = -31\\-4c_{1}+c_{2} = -15

There are several methods to solve this system. One of them is to multiply the second equation to -1 and add both equations:

6c_{1}+c_{2} = -31\\(-1)*-4c_{1}+c_{2} = -15*(-1)

6c_{1}+c_{2} = -31\\4c_{1}-c_{2} = 15

10c_{1} = -16

c_{1} = \frac{-16}{10}

With c_{1}, substitute in one of the equations and find c_{2}:

6c_{1}+c_{2}=-31

c_{2}=-31-6(\frac{-16}{10} )

c_{2}=-31+(\frac{96}{10} )

c_{2}=\frac{-310+96}{10}

c_{2}=\frac{-214}{10}

<u>For the equation, </u>c_{1} = \frac{-16}{10}<u> and </u>c_{2}=\frac{-214}{10}<u />

6 0
1 year ago
The annual interest rate of Daphne's savings account is 2.4% and simple interest is calculated semiannually. What is the periodi
alexdok [17]
The interest rate is calculated semiannually which means twice a year so you do 2.4/2 which equals 1.2 so the answer is D
4 0
2 years ago
Antonio's toy boat is bobbing in the water under a dock. The vertical distance HHH (in \text{cm}cmstart text, c, m, end text) be
musickatia [10]

Answer: Time t = 33.0 seconds

Step-by-step explanation:

Given that the vertical distance H between the dock and the top of the boat's mast t seconds after its first peak is modeled by the function

H(t) = 5cos( 2π/3 ​t) − 35.5H

Where the maximum vertical distance = 5

At the down position, H(t) = 0

5cos( 2π/3 ​t) − (35.5/100)H = 0

5cos( 2π/3 ​t) − 0.355 × 5 =0

5cos( 2π/3 ​t) − 0.1775 = 0

5cos( 2π/3 ​t) = 0.1775

cos( 2π/3 ​t) = 0.1775/5

cos( 2π/3 ​t) = 0.355

2π/3 ​t = cos^-1 (0.355)

2π/3 ​t = 69.2

2πt = 69.2 × 3

2πt = 207.6

t = 207.6/2π

t = 33.0 seconds

3 0
2 years ago
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Find the standard deviation of the following data. Answers are rounded to the nearest tenth. 5, 5, 6, 12, 13, 26, 37, 49, 51, 56
kogti [31]

Answer:

24.2(to the nearest tenth)

Step-by-step explanation:

The question is ungrouped data type

standard deviation =√ [∑ (x-μ)² / n]

mean (μ)=∑x/n

           = \frac{5+5+6+12+13+26+37+49+51+56+56+84}{12}

          =33.3

x-μ   for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be

                   -28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49

∑ (x-μ)² will be = 7028.59

standard deviation = √(7028.59 / 12)

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6 0
2 years ago
This chart shows what happens when each object is placed on a balance with a 10 kg weight on the other side.
dexar [7]

9514 1404 393

Answer:

  Object 1 is the heaviest object.

Step-by-step explanation:

The first column of the table tells you ...

  Object 1 is heavier than the 10 kg weight

The second column of the table tells you ...

  Object 2 weighs 10 kg

The third column of the table tells you ...

  Object 3 is lighter than the 10 kg weight

Then the relative weights are ...

  Object 1 > Object 2 > Object 3

That is, Object 1 is the heaviest object.

8 0
1 year ago
Read 2 more answers
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