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2 years ago

A matrix contains 60 elements. Which of the following cannot equal the number of rows of the matrix?

Mathematics

1 answer:

avanturin [10]2 years ago

6 0

Given:

Matrix = 60 elements

To solve this, we need to take into account that each row must contain the same number of elements. So, we need to find which of the options do not divide evenly into 60 (the options are 30, 60, 10, and 18).

So we check each of the choices to see if 1 of them divides evenly with 60.

60 / 60 = 1 (divides evenly)

60 / 30 = 2 (divides evenly)

60 / 10 = 6 (divides evenly)
60 / 18 = 3.3.3333333333333333333333333333333 (does not divide evenly)

Therefore, 18 cannot equal the number of rows of the matrix.

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A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe

xxMikexx [17]

Answer:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

Step-by-step explanation:

For the random variable $N_1$ we define the possible values for this variable on this case $[1,2,3,4,5]$ . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

$5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10$

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

8 0

1 year ago

Calculate the side lengths a and b to two decimal places

Talja [164]

Answer:

The answer is (D) ⇒ a = 11.71 , b = 15.56

Step-by-step explanation:

* In ΔABC

∵ m∠A = 45°

∵ m∠B = 110°

∴ m∠C = 180 - 45 - 110 = 25°

By using the sin Rule

∵ a/sin(A) = b/sin(B) = c/sin(C)

∵ c = 7

∴ a/sin(45) = b/sin(110) = 7/sin(25)

∴ a = (7 × sin(45)) ÷ sin(25) = 11.71

∴ b = (7 × sin(110)) ÷ sin(25) = 15.56

∴ The answer is (D)

5 0

2 years ago

En el juego de domino son 28 fichas con la cara hacia abajo cual es la probabilidad de sacar la ficha 6-7

9966 [12]

Shakin my head like yeah

7 0

2 years ago

circle o is inscribed in triangle rst such that it is tangent at points m,n, and p. if rp is 7, rt is 17 and sm is 5, then what

zloy xaker [14]

Answer:

The length of side st is 15.

Step-by-step explanation:

A tangent is a straigth line that touches a circle externally at a point on the circumference. Considering one of its properties that tangents from the same point to a fixed point outside a circle are equal.

Then,

/rn/ = /rp/

/tm/ = /tn/

/sm/ = /sp/

But, /rp/ = 7, /rt/ = 17 and /sm/ = 5.

Then,

/rt/ = /rn/ + /tn/

17 = 7 + /tn/ (∵ /rp/ = /rn/ = 7)

⇒ /tn/ = 10

Since /nt/ = 10, then /tm/ = 10 (/tm/ = /nt/)

So that,

/st/ = /sm/ + /tm/

= 5 +10

/st/ = 15

The length of side st is 15.

7 0

2 years ago

PLZ HELP I WILL GIVE BRAINLIEST!!

VladimirAG [237]

Answer:

Part A

16 and 1/2 or 16 R6, 17 if you round up

Part B

Answer choices A and D are correct

6 0

2 years ago