Ask question

Ask question

All categories

2 years ago

15

At a baseball game, 89% of people attending were supporting the home team, while 11% were supporting the visiting team. If 2314

people attending the game supported the home team, what was the total number of people attending the game?

1 answer:

pickupchik [31]2 years ago

3 0

Answer:

2600

Step-by-step explanation:

2314 ÷ 89% = 2600

2314 is 89% of 2600.

You might be interested in

Alex started a new social media account,which he used to post pictures of cute animals. On the first day he only had 8 followers

Hatshy [7]

Answer:

648 followers

Step-by-step explanation:

Let first day=a1

Tripled followers everyday

Second day=a2=a1×3

Third day=a3=a2*3

Fourth day=a4=a3*3

Fifth day=a5=a4*3

a=8 followers

a2=a1×3

=3*8

=24 followers

a3=a2*3

=24*3

=72 followers

a4=a3*3

=72*3

=216 followers

a5=a4*3

=216*3

=648 followers

On the fifth day, Alex will have a total of 648 followers on his new social media account.

7 0

2 years ago

Nick has to build a brick wall. Each row of the wall requires 62 bricks. There are 10 rows in the wall. How many bricks will Nic

Delicious77 [7]

10 x 62 is the equation for this problem because every row has 62 and there are 10 rows.

7 0

2 years ago

Find the value of x in each case:

Zanzabum

Answer:

$x=30\°$

Step-by-step explanation:

<u>Find the measures of interior angles in each triangle</u>

Triangle BGC

$m$

The measures of triangle BGC are $90\°-60\°-30\°$

Triangle CGH

we know that

$m$ -----> by consecutive interior angles

we have that

$m$

so

$m$

$m$

substitute

$m$

we have

$m$

$m$

$m$

remember that

$m$

$60\°+2x+180\°-4x=180\°$

$60\°=2x$

$x=30\°$

The measures of triangle CGH are $60\°-60\°-60\°$

Triangle GHE

$m< EGH=90\°-2x=90-2(30\°)=30\°$

$m< GHE=4x=4(30\°)=120\°$

remember that

$m$

substitute and solve for m<GEH

$30\°+120\°+m$

$150\°+m$

$m$

The measures of triangle GHE are $30\°-120\°-30\°$

6 0

2 years ago

Read 2 more answers

Gretchen made $56,750 last year. She paid $1,200 in student loan interest and made a $3,000 contribution to her IRA. On her fede

tia_tia [17]

d. Adjustments

Studen loan interests and IRA contributions are deductions found under the heading of ADJUSTMENTS TO INCOME to compute for the Adjusted Gross Income or AGI.

Standard deductions are those based on the filing status of the individual and not his total itemized deductions. Regardless of the actual expenses incurred by an individual, he can claim a standar deduction if he is single, head of household, married filing separately, married filing jointly, qualifying widow(er). at the time he files for his federal tax return.

taxable income is the income left from all the necessary deductions.

For example: Gretchen's income => $56,750
   less: Adjustments to income
   student loan interest $1,200
   IRA Contribution 3,000 - 4,200
   ===========
Taxable income $52,550

8 0

2 years ago

Read 2 more answers

Researchers from Dartmouth Medical School conducted a study in 2003 to look at the connection between watching actors smoking in

docker41 [41]

Answer:

The 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies is (0.37, 0.40).

Step-by-step explanation:

A confidence interval is an interval estimate of the population parameter. The confidence interval has a certain probability of consisting the true value of the parameter.

The (1 - <em>α</em>) % confidence interval for the population proportion (<em>p</em>) is given by:

$CI=\hat p\pm z_{\alpha/2}\times \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

$n = 6522\\\hat p=0.38\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Use a <em>z</em>-table for the critical value.

Construct the 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies as follows:

$CI=\hat p\pm z_{\alpha/2}\times \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.38\pm 1.96\times \sqrt{\frac{0.38(1-0.38)}{6522}}\\=0.38\pm 0.0118\\=(0.3682, 0.3918)\\\approx (0.37, 0.40)$

Thus, the 95% confidence interval for the proportion of adolescents who tried smoking for the first time because of exposure to smoking in the movies is (0.37, 0.40).

8 0

1 year ago