Answer:
Insurance will pay $250,000 and Ronaldo will pay $90,000
Step-by-step explanation:
50/250 means 50 is the maxi9$50,000 per person for body injury liability while 250 means $250,000 maximum for one accident for body injury liability claim.
18 children each was awarded $20,000 as a result of lawsuit
Total amount of lawsuit=18×$20000= $360000
Ronald has 50/250 BI
Total amount insurance will pay =250,000
Ronald will have to pay= $(360,000-250000)=$90,000
Since the sum of scores must be at least 289:
72+78+70+x ≥ 289
Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
Answer:
Step-by-step explanation:
From the question, we can form an equation like: S = 7200 + 350X
where S is the salary and X is year.
1. His salary in the 9th year, means X=9, so we substitute 9 into the equation to find S = 7200 +350 (9) = 10350
2. The total he will have in the first 12years, we have:
Sum of first n terms of an <em><u>AP: S =(n/2)[2a + (n- 1)d]</u></em> where a is the value of the 1st term, here a is 7200 and d = 350 the common difference between terms
=> S = (12/2)[2*7200 + (12- 1)350] = 109500
Answer:
a) Cost

b) Sales income

c) Table of values
![\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dq%26C%28q%29%26S%28q%29%5C%5C0%2650%260%5C%5C250%264%2C050%265%2C000%5C%5C500%268%2C050%2610%2C000%5Cend%7Barray%7D%5Cright%5D)
d) Attached
e) Breakeven point = 12.5 sheets
f) Profit at 550 sheets = $1,950
Step-by-step explanation:
a) We have a fixed cost for the image, at $50.
We also have a variable cost of $16 a sheet.
The purchased quantity is 500 sheets.
Then, the cost function is:

b) The price for each sheet is $20, so the income from sales are:

c) Table of values
![\left[\begin{array}{ccc}q&C(q)&S(q)\\0&50&0\\250&4,050&5,000\\500&8,050&10,000\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dq%26C%28q%29%26S%28q%29%5C%5C0%2650%260%5C%5C250%264%2C050%265%2C000%5C%5C500%268%2C050%2610%2C000%5Cend%7Barray%7D%5Cright%5D)
d) Attached
e) The minimum number of sheets the group must sell so they don't lose any money is the breakeven point (BEP) and can be calculated making the income sales equal to the cost:

f) This profit can be calculated as the difference between the sales income and the cost:
