2.8y + 6 + 0.2y = 5y – 14
Simplify the left side:
3y +6 = 5y-14
Subtract 3y from both sides:
6 = 2y -14
Add 14 to each side:
2y =20
Divide both sides by 2:
y = 20 / 2
y = 10
as you already know, the equation y=-7/4x-2, is already in slope-intercept form and thus its slope is the coefficient of the "x", namely -7/4.
parallel lines have the same exact slope, so a parallel line to this one will also have a slope of -7/4, and it passes through 4,2,

Answer:
I'm not sure for which answer you're asking for so I'll give you all of them. On the tenth day, Chris will give away 1024 cards.
Step-by-step explanation:
On the fourth day he will give away 16, on the fifth day 32, on the sixth day 64, on the seventh say 132, on the eighth day 264, on the ninth day 528, and on the tenth day 1024
Answer:
1.734
Step-by-step explanation:
Given that:
A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).
The fitted regression is Time = −7.126 + .0214 Distance
Based on a sample size n = 20
And an Estimated standard error of the slope = 0.0053
the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:
Let's determine the degree of freedom df = n - 1
the degree of freedom df = 20 - 2
the degree of freedom df = 18
At the level of significance ∝ = 0.05 and degree of freedom df = 18
For a right tailed test t, the critical value from the t table is :
1.734
Well, quadratic equations are defined as to be 2nd degree, so since the highest degree (3) is being raised to the 2nd degree raising it to 6th power which makes th equaton no longer quadraic
take out all exponents over x
16(x+1)^2-22(x+1)-3=0
16(x^2+2x+1)-22x-22-3=0
16x^2+32x+32-22x-25=0
16x^2+10x+7=0
the replacement is to take out all exponents that are over x (x^m should be turned to x^1)