My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour.For ho
2 answers:
Solution:
we are given that
My friend sets out walking at a speed of 3 miles per hour.
I set out behind her 5 minutes later at 4 miles per hour.
we have been asked to find
For how many minutes will my friend have been walking when I catch up to her?
Let the required time be t then we can write
As we know that
When they meet up then difference of distance traveled becomes zero.
so we can write
Hence the required time is 20 minutes.
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Answer:
Step-by-step explanation:
Previous concepts
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:
And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:
Or equivalently:
Solution to the problem
For this case we are interested in the total T, and we can find the mean and deviation for this like this:
If we solve for T we got:
And the expected value is given by:
And we can find the variance like this:
And then the deviation is given by:
And the distribution for the total is:
And we want to find this probability:
And we can use the z score formula given by:
And replacing we got this:
Answer:
answer is
Step-by-step explanation:
After working this way for 6 months he takes a simple random sample of 15 days. He records how long he walked that day (in hours) as recorded by his fitness watch as well as his billable hours for that day as recorded by a work app on his computer.
Slope is -0.245
Sample size n = 15
Standard error is 0.205
Confidence level 95
Sognificance level is (100 - 95)% = 0.05
Degree of freedom is n -2 = 15 -2 = 13
Critical Value =2.16 = [using excel = TINV (0.05, 13)]
Marginal Error = Critical Value * standard error
= 2.16 * 0.205
= 0.4428
Answer:
Part A
Please see attached the required stem and leaf plot
For the stem and leaf plot, the nonsplit system is used because of clarity for analysis
Part B:
From the shape of the stem and leaf plot we have that there is an average increase of pulse rate of 20 pulses in all the 19 students after the exercise
The shape of the plot is relatively the same for the before and after exercise save for the decrease in the third to the last row by one and the increase in the second to the last roe by one student
The spread remained relatively constant in both cases with the most being in the 60s range having 7 students in the before exercise and the 80s range having 8 students in the after exercise leaf plot.
Step-by-step explanation:
The given data are;
67 87
67 88
67 89
68 89
71 91
72 93
72 93
75 95
77 96
77 97
79 98
81 98
85 101
87 105
87 105
91 119
97 125
103 125
121 147
