Ask question

Ask question

All categories

Marina CMI [18]

1 year ago

11

A piece of climbing equipment at a playground is 6 feet high and extends 4 feet horizontally. A piece of climbing equipment at a

gym is 10 feet high and extends 6 feet horizontally. Which statement best compares the slopes of the two pieces of equipment?

2 answers:

daser333 [38]1 year ago

7 0

<span>Because5/3 >3/2 , the slope of the climbing equipment at the gym is greater.</span>

Dahasolnce [82]1 year ago

5 0

Answer: The comparison is mentioned below.

Step-by-step explanation:

A piece of climbing equipment at a playground is 6 feet high and extends 4 feet horizontally.

Therefore its slope = length of the equipment vertically / length of equipment horizontally

$m_1$ = 6/4 = 3/2 = 1.5

And, A piece of climbing equipment at a gym is 10 feet high and extends 6 feet horizontally.

Therefore slope, $m_2$ = 10/6 = 5/3=1.67 (approx)

Since, $m_1$ < $m_2$

Thus the slope of equipment first is less than slope of second equipment.

You might be interested in

A number x, rounded to 1 decimal place is 12.3 write down the error interval for x

icang [17]

We know that
<span>A number x, rounded to 1 decimal place is 12.3
</span><span>so
x>=12.25
and
x < 12.35

</span><span>the error interval for x is the interval [12.25,12.35)
</span>
the answer is
[12.25,12.35)

3 0

1 year ago

The height of a cylinder is twice the radius of its base. A cylinder has a height of 2 x and a radius of x. What expression repr

cluponka [151]

<h2>Answer:</h2><h2>volume of the cylinder = 2π $x^{3}$ </h2>

Step-by-step explanation:

The height of a cylinder is twice the radius of its base.

Let the height of the cylinder = 2x

Let the radius of the cylinder = x

By formula, volume of the cylinder = π $r^{2}$ h

here r = x, h = 2x

substituting the values in the equation, we get

volume of the cylinder = π $r^{2}$ h = π $x^{2}$ (2x)

volume of the cylinder = 2π $x^{3}$

5 0

2 years ago

Read 2 more answers

In ΔMNO, the measure of ∠O=90°, ON = 65, MO = 72, and NM = 97. What is the value of the tangent of ∠M to the nearest hundredth?

PilotLPTM [1.2K]

Answer:

Therefore the value of tangent of ∠ $M$ is $42$ °.

Step-by-step explanation:

Given that,

In Δ $MNO$ , ∠ $O=90$ °, $ON=65,$ $MO=72,$ and $NM=97.$

and we have to find the value of tangent of ∠ $M.$

Diagram of the given triangle is shown below:

Now,

Δ $MNO$ is a right angle triangle, so we can use all the trigonometric ratio.

$sin\alpha =\frac{Perpendicular}{Hypotenuse}$

$cos\alpha =\frac{Base}{Hypotenuse}$

$tan\alpha =\frac{sin\alpha }{cos\alpha }$ = $\frac{Perpendicular}{Base}$

tangent of ∠ $M$ = $\frac{Perpendicular}{Base}$

= $\frac{ON}{MO}$

= $\frac{65}{72}$

= $0.90278$

∴∠ $M$ = $tan^{-1} (0.90278)$

= $42.0750$ ° ≅ $42$ °

Therefore the value of tangent of ∠ $M$ is $42$ °.

4 0

1 year ago

Triangle N T M is shown. Angle N T M is a right angle. An altitude is drawn from point T to point U on side N M to form a right

stich3 [128]

Answer:

The value of y is 6 $\sqrt{3}$ units ⇒ 2nd answer

Step-by-step explanation:

In the attached figure

∵ ∠MTN is a right angle

∵ TU is the altitude of the triangle

- There are some rules in this triangle let us revise them

(NT)² = NU . NM
(MT)² = MU . MN
(TU)² = MU . NU
TM . TN = TU . MN

∵ NU = 9 units

∵ UM = 3 units

∵ MN = UM + NU

∴ MN = 3 + 9 = 12 units

- By using the 1st rule above

∴ (NT)² = 9 × 12

∴ (NT)² = 108

- Take a square root to both sides

∴ NT = $\sqrt{108}$

- Simplify the root

∴ NT = 6 $\sqrt{3}$ units

∵ NT is y

∴ y = 6 $\sqrt{3}$ units

The value of y is 6 $\sqrt{3}$ units

8 0

1 year ago

Read 2 more answers

Matt Adams is the best player in his college baseball team. In his last few games, Matt has hit 70%, 77% 81% and 88% of balls th

Ksivusya [100]

79 is the answer ........

6 0

1 year ago

Read 2 more answers