Answer:
Step-by-step explanation:
Confidence interval is written in the form, sample mean ± margin of error
The sample mean is an estimator for the population mean. The confidence level is used to express how confident we are that the population mean is within the calculated confidence interval. The lower limit of the given confidence interval is 2.619 hours/day while the upper limit of the confidence interval is 3.401 hours/day
Therefore, the INVALID interpretations of the 95% confidence interval are
A. About 95% of all Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.
B. There is a 95% chance that, on average, Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.
D. In the long run, 95% of the sample means will be between 2.619 and 3.401 hours.
E. None of the above.
Elisa, e = 11mins
Prenav,p = 13mins
time to complete, t
1 = t( 1/11 + 1/13) = t (24/143)
t = 143/24 = 5.96min
Answer is A 5.96mins
Answer:
Step-by-step explanation:
you have to make a box like this:
║ ---------- ║------------ ║ label one side percent and the other amount
║ x% ║ 96 kg ║
║ _ _ _║_____ _║ Now if the patient originally weighed 102 kg which
║100% ║ 120 kg ║ is 100% place the numbers in the bottom box.
║ _ _ _ ║ _ _ _ ║ and if the patient currently weighs 96 kg then let
Percent Amount percentage of the weight lost be x. Now cross multiply. You should get 100*96=120*x. Simplify that to get 9600=120x, now divide by 120 on both sides and you get 80 so x= 80. But the problem isn't done yet. Now you have to subtract 80% from 100% to find the weight lost, because 80% is the percentage of the current weight. after you have subtracted you get 20
20% of the original weight was lost.
Answer:
W= 27 k J
Step-by-step explanation:
Given that
mass ,m = 90 kg
Height , h= 30 m
angle , θ = 25°
The work done by escalator is given as follows
W = m g h
Work done by escalator does not depends on the angle ,it depends only on height.
Now by by putting the values in the above equation we get
W= 90 x 10 x 30 J ( take g = 10 m/s² )
W= 27000 J
W= 27 k J
Therefore work done by escalator will be 27 k J.
