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MrRa [10]
2 years ago
6

Maddie's monthly take home pay is $3,500. She is making monthly payments of $250 for a student loan and $218 for a credit card.

What is the maximum monthly car payment she can make without going in credit overload?
Mathematics
1 answer:
iren2701 [21]2 years ago
4 0

Answer:

C. $482

Step-by-step explanation:

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At the store a cell phone cost 1.1 times as much as it sells online. If it cost $888.98 online, how much more does it cost from
Airida [17]

Given:

At the store a cell phone cost 1.1 times as much as it sells online.

The cost of it is $888.98 online.

To find:

How much more does it cost from the store?

Solution:

It is given that,

Cost of a cell phone online = $888.98

At the store a cell phone cost 1.1 times as much as it sells online. So, cost of the cell phone at store is

1.1\times (888.98)=977.878


The cost of cell phone at store is $977.878 .

The difference between the cost of cell phone at store and online is

\$977.878
-\$888.98=\$88.898

Therefore, the cell phone cost is $88.898 much more at the store.

8 0
2 years ago
A restaurant noted what type of food its customers purchased last week. Here are the results: burger 15% fries 10 % both 55% out
mixer [17]

Answer:

(a) Not mutually exclusive

(b)80%

Step-by-step explanation:

Mutually Exclusive events are events which cannot occur at the same time. An example is walking forward and backward. When events are presented using Venn diagram, if the sets are disjoint, they are mutually exclusive, otherwise they are not.

(a)The given events "burger" and "fries" are not mutually exclusive since their intersection is not empty as can be seen from the attached Venn diagram.

(b) Probability that a randomly selected person from this sample bought a burger OR bought fries.

P(A or B)=P(A\cup B)=80\%

6 0
2 years ago
Which of the following statements is true? a. sin 30° = cos 30° b. sin 35° = cos 55° c. sin 60° = cos 60° d. sin 55° = cos 25°
Makovka662 [10]
<span>b. sin 35° = cos 55° is the correct answer i believe :)</span>
6 0
2 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.
IrinaVladis [17]

Answer:  C= (3,2) and D=(2.2, 2.8)

Step-by-step explanation:

The coordinates of point P(x,y) divides a line segment having end points M{x_1,y_1} and N(x_2,y_2) in m:n will be :-

x=\dfrac{mx_2+nx_1}{m+n}\ ;\ y=\dfrac{my_2+ny_1}{m+n}

Given : The endpoints of AB are A(1,4) and B(6,-1).

If point C divides AB in the ratio 2 : 3, the coordinates of point C will be :-

x=\dfrac{2(6)+3(1)}{2+3}\ ;\ y=\dfrac{2(-1)+3(4)}{2+3}

Simplify,

\\\\\Rightarrow x=3\ y=2

Thus , coordinate of C= (3,2)

If point D divides AC in the ratio 3 : 2, the coordinates of point D will be :-

x=\dfrac{3(3)+2(1)}{3+2}\ ;\ y=\dfrac{3(2)+2(4)}{3+2}

Simplify,

\\\\\Rightarrow x=3\ y=2

Thus , coordinate of D= (2.2,2.8)

4 0
2 years ago
Read 2 more answers
A batch of 445 containers for frozen orange juice contains 3 that are defective. Two are selected, at random, without replacemen
Elan Coil [88]

Answer:

  1. When Two containers are selected

(a) Probability that the second one selected is defective given that the first one was defective = 0.00450

(b) Probability that both are defective = 0.0112461

(c) Probability that both are acceptable = 0.986

    2. When Three containers are selected

(a) Probability that the third one selected is defective given that the first and second one selected were defective = 0.002.

(b) Probability that the third one selected is defective given that the first one selected was defective and the second one selected was okay = 0.00451

(c) Probability that all three are defective = 6.855 x 10^{-8} .  

Step-by-step explanation:

We are given that a batch of 445 containers for frozen orange juice contains 3 defective ones i.e.

                  Total containers = 445

                   Defective ones   = 3

           Non - Defective ones = 442 { Acceptable ones}

  • Two containers are selected, at random, without replacement from the batch.

(a) Probability that the second one selected is defective given that the first one was defective is given by;

  <em>Since we had selected one defective so for selecting second the available </em>

<em>   containers are 444 and available defective ones are 2 because once </em>

<em>    chosen they are not replaced.</em>

Hence, Probability that the second one selected is defective given that the first one was defective = \frac{2}{444} = 0.00450

(b) Probability that both are defective = P(first being defective) +

                                                                     P(Second being defective)

                 = \frac{3}{445} + \frac{2}{444} = 0.0112461

(c) Probability that both are acceptable = P(First acceptable) +  P(Second acceptable)

Since, total number of acceptable containers are 442 and total containers are 445.

 So, Required Probability = \frac{442}{445}*\frac{441}{444} = 0.986

  • Three containers are selected, at random, without replacement from the batch.

(a) Probability that the third one selected is defective given that the first and second one selected were defective is given by;

<em>Since we had selected two defective containers so now for selecting third defective one, the available total containers are 443 and available defective container is 1 .</em>

Therefore, Probability that the third one selected is defective given that the first and second one selected were defective = \frac{1}{443} = 0.002.

(b) Probability that the third one selected is defective given that the first one selected was defective and the second one selected was okay is given by;

<em>Since we had selected two containers so for selecting third container to be defective, the total containers available are 443 and available defective containers are 2 as one had been selected.</em>

Hence, Required probability = \frac{2}{443} = 0.00451 .

(c) Probability that all three are defective = P(First being defective) +

                              P(Second being defective) +  P(Third being defective)

        = \frac{3}{445}* \frac{2}{444}  * \frac{1}{443} = 6.855 x 10^{-8} .                

               

5 0
2 years ago
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