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2 years ago

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Maddie's monthly take home pay is $3,500. She is making monthly payments of $250 for a student loan and $218 for a credit card.

What is the maximum monthly car payment she can make without going in credit overload?

1 answer:

iren2701 [21]2 years ago

4 0

Answer:

C. $482

Step-by-step explanation:

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Jaina and Tomas compare their compound interest accounts to see how much they will have in the accounts after three years. They

MariettaO [177]

The question is incomplete. The complete question is :

Jaina and Tomas compare their compound interest accounts to see how much they will have in the accounts after three years. They substitute their values shown below into the compound interest formula. Compound Interest Accounts Name Principal Interest Rate Number of Years Compounded Jaina $300 7% 3 Once a year Tomas $400 4% 3 Once a year. Which pair of equations would correctly calculate their compound interests?

Solution :

It is given that Jaina and Tomas wants to open an account by depositing a principal amount for a period of 3 years and wanted to calculate the amount they will have using the compound interest formula.

<u>So for Jiana</u> :

Principal, P = $300

Rate of interest, r = 7%

Time, t = 3

Compounded yearly

Therefore, using compound interest formula, we get

$A=P\left(1+\frac{r}{100}\right)^{t}$

$=300\left(1+\frac{7}{100}\right)^{3}$

$=300(1+0.07)^3$

<u>Now for Tomas </u>:

Principal, P = $400

Rate of interest, r = 4%

Time, t = 3

Compounded yearly

Therefore, using compound interest formula, we get

$A=P\left(1+\frac{r}{100}\right)^{t}$

$=400\left(1+\frac{4}{100}\right)^{3}$

$=400(1+0.04)^3$

Therefore, the pair of equations that would correctly calculate the compound interests for Jaina is $A=300(1+0.07)^3$ .

And the pair of equations that would correctly calculate the compound interests for Tomas is $A=400(1+0.04)^3$ .

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The average American man consumes 9.8 grams of sodium each day. Suppose that the sodium consumption of American men is normally

Alex Ar [27]

Answer:

(a) The distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b) The probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c) The middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

Step-by-step explanation:

The random variable <em>X</em> is defined as the amount of sodium consumed.

The random variable <em>X</em> has an average value of, <em>μ</em> = 9.8 grams.

The standard deviation of <em>X</em> is, <em>σ</em> = 0.8 grams.

(a)

It is provided that the sodium consumption of American men is normally distributed.

The random variable <em>X</em> follows a normal distribution with parameters <em>μ</em> = 9.8 grams and <em>σ</em> = 0.8 grams.

Thus, the distribution of <em>X</em> is <em>N</em> (9.8, 0.8²).

(b)

If X ~ N (µ, σ²), then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z ~ N (0, 1).

To compute the probability of Normal distribution it is better to first convert the raw score (<em>X</em>) to <em>z</em>-scores.

Compute the probability that an American consumes between 8.8 and 9.9 grams of sodium per day as follows:

$P(8.8$

$=P(-1.25$

Thus, the probability that an American consumes between 8.8 and 9.9 grams of sodium per day is 0.4461.

(c)

The probability representing the middle 30% of American men consuming sodium between two weights is:

$P(x_{1}$

Compute the value of <em>z</em> as follows:

$P(-z$

The value of <em>z</em> for P (Z < z) = 0.65 is 0.39.

Compute the value of <em>x</em>₁ and <em>x</em>₂ as follows:

$-z=\frac{x_{1}-\mu}{\sigma}\\-0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8-(0.39\times 0.8)\\x_{1}=9.488\\x_{1}\approx9.5$ $z=\frac{x_{2}-\mu}{\sigma}\\0.39=\frac{x_{1}-9.8}{0.8}\\x_{1}=9.8+(0.39\times 0.8)\\x_{1}=10.112\\x_{1}\approx10.1$

Thus, the middle 30% of American men consume between 9.5 grams to 10.1 grams of sodium.

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