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weeeeeb [17]
2 years ago
15

A school principal wants to determine which subject the 800 students in his school like best.

Mathematics
1 answer:
timofeeve [1]2 years ago
6 0
The answer is c. a selection of 80 students in the school
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In a circle with center C and radius 6, minor arc AB has a length of 4pi. What is the measure, in radians, of central angle ACB?
valina [46]
To solve this problem, we need to know that 
arc length = r θ  where θ is the central angle in radians.

We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3

Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
8 0
2 years ago
Read 2 more answers
Consider the incomplete paragraph proof. Given: Isosceles right triangle XYZ (45°–45°–90° triangle) Prove: In a 45°–45°–90° tria
Norma-Jean [14]

Answer:

(C)Determine the principal square root of both sides of the equation.

Step-by-step explanation:

Given: Isosceles right triangle XYZ (45°–45°–90° triangle)

To Prove: In a 45°–45°–90° triangle, the hypotenuse is \sqrt{2} times the length of each leg.

Proof:

\angle XYZ$ is 90^\circ$ and the other 2 angles are 45^\circ. \\\overline{XY} = a, \overline{YZ}= a, \overline{XZ}= c.\\

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a^2 + b^2 = c^2

Since a=b in an isosceles triangle:

a^2 + a^2 = c^2\\$Combining like terms\\2a^2 = c^2\\$Determine the principal square root of both sides of the equation.\\\sqrt{c^2}=\sqrt{2a^2}  \\\\c=a\sqrt{2} \\

Therefore, the next step is to Determine the principal square root of both sides of the equation.

8 0
1 year ago
Read 2 more answers
The ratio of teachers needs to be 1:30. If there were 120 students, how many teachers would be needed?
mezya [45]

Answer:

4:120

Step-by-step explanation:

for 120 student they would be 4 teacher needed per 30 student

4:120

4 0
2 years ago
What is the common ratio between successive terms in the sequence 1.5, 1.2, 0.96, 0.768
Pani-rosa [81]

Answer:

To determine the common ratio of a geometric sequence. You just need to divide any two consecutive terms on it. You can see below that all of them have the same quotient.

1.2 / 1.5 = 0.8

0.96 / 1.2 = 0.8

0.768 / 0.96 = 0.8

.

Decimal form = 0.8

Fraction form = 4/5

.

Check:

1.5 x 0.8 = 1.2

1.5 x 4/5 = 6/5 = 1 1/5 = 1.2

Therefore, the common ratio between successive terms in the sequence? 1.5, 1.2, 0.96, 0.768 is 0.8 or 4/5.

6 0
2 years ago
Each gallon of paint covers $200$ square feet. I have to paint one side of a wall that is $12$ meters tall and $80$ meters long.
dsp73

Answer:

make those cheeks go in circuler motion

Step-by-step explanation:

5 0
2 years ago
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