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Tom [10]
2 years ago
13

Jimmy made a 15% profit on the sale of a custom designed boat, and the original cost of the boat was $15,000. The boat sold for

how much? 
Mathematics
2 answers:
Anestetic [448]2 years ago
6 0
If jimmy made a profit of 15% than u would do 15,000 of 15% and that would be 2,250
but that would be Jimmy's profit
Now, what u would do to get how much the boat was sold, than u would do 15,000-2,250 
and the answer will be 12,750 
wel2 years ago
3 0

Answer:

the boat was sold for $17,250

Step-by-step explanation:

Jimmy made a 15% profit, that means that  the 15% of the cost is going to be his profit, so the 15% of $15,000 is:

$15,000(0.15)= $2,250

If his profit is 2,250, the price of the boat is going to be the initial cost plus the profit. So:

Price=$15,000 + $2,250 = $ 17,250

Then, the boat was sold for $17,250

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2.8, 3.4, 4.0, 4.6, . . . Write an equation for the nth term of the arithmetic sequence. Then find a50.
vova2212 [387]

Answer:

a_n = 2.2 + 0.6 n

a_50 = 32.2

Step-by-step explanation:

What's the common difference of this series?

a_1 = 2.8

a_2 = 3.4

Common difference = a_2 - a_1 = 3.4 - 2.8 = 0.6.

Expression for the nth term:

a_n = a_1 + (n - 1) \cdot\text{Common Difference} \\\phantom{a_n } = 2.8 + 0.6 \; (n-1) \\\phantom{a_n} = 2.8 + 0.6 \; n - 0.6\\\phantom{a_n} = 2.2 + 0.6\; n

n = 50 for the fiftieth term. Therefore

a_{50} = 2.2 + 0.6 \times 50 = 32.2.

6 0
2 years ago
Mr. Lobo is building a fence rectangular around his rectangular yard. It is 16 feet long and 14 feet wide. How much feet of feet
lawyer [7]

Answer:

30

Step-by-step explanation:

14+16 1. Break it down 14 is equal to 10+4 16 is equal to 10+6 2. Add the biggest numbers together first 10+10 = 20 3. Add the smaller numbers together 6+4 = 10 4. Add all of the numbers together 20+10 = 30

4 0
2 years ago
32​% of U.S. adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find t
Lorico [155]

Answer:

A.  21.06%

B. 66.88%

C. 81.56%

Step-by-step explanation:

There are two possible answer for the question asked, yes(more likely to make purchases) or no. The probability for a random adults answer yes to the question is 32% so the probability that the adults answer no is 68%.

(a) exactly​ two

There is only one case for this question, 2 people say yes and 8 people say no. The calculation for this problem will be:

2P10 * P(yes)^2 * P(no)^8= 10!/2!8!* 32%^2  * 68%^8 = 0.21066= 21.06%

(b) more than​ two

There are a lot of case for more than two, its easier to find out the negation of the probability which is "two or less". Case that fulfill "two or less" will be: 2 yes and 8 no

1 yes and 9 no

0 yes and 10 no

The calculation for the negation will be:

~P(X)= 0P10 * P(yes)^0 * P(no)^10   +   1P10 * P(yes)^1 * P(no)^9   +  2P10 * P(yes)^2 * P(no)^8  =

10!/0!10!* 32%^0  * 68%^10    +   10!/1!9!* 32%^1  * 68%^9   +   10!/2!8!* 32%^2  * 68%^8

0.02113 + 0.09947 + 0.21066  =  0.33126= 33.12%

Since its the negation, you need to subtract 1 with the negation

P(X)= 1 - ~P(X)

P(X)= 1 - 33.12%= 66.88%

(c) between two and​ five, inclusive

Same formula as above, but the case is:

2 yes and 8 no

3 yes and 7 no

4 yes and 6 no

5 yes and 5 no

The calculation will be:

2P10 * P(yes)^2 * P(no)^8 + 3P10 * P(yes)^3 * P(no)^7 + 4P10 * P(yes)^4 * P(no)^6 + 5P10 * P(yes)^5 * P(no)^5 =

10!/2!8!* 32%^2  * 68%^8    +   10!/3!7!* 32%^3  * 68%^7   +   10!/4!6!* 32%^4  * 68%^6  +  10!/5!5!* 32%^5  * 68%^5

0.21066 + 0.26435 + 0.21770 + 0.1229= 0.81561= 81.56%

8 0
2 years ago
Prove that (sec 12A-1)/(sec 6A-1)=tan 12A/tan 3A
adelina 88 [10]

Let x=3A. Recall the following identities,

\cos^2\theta=\dfrac{1+\cos2\theta}2

\sin^2\theta=\dfrac{1-\cos2\theta}2

\sin2\theta=2\sin\theta\cos\theta

Now,

\dfrac{\sec12A-1}{\sec6A-1}=\dfrac{\sec4x-1}{\sec2x-1}

=\dfrac{\cos2x(1-\cos4x)}{\cos4x(1-\cos2x)}

=\dfrac{2\cos2x\sin^22x}{\cos4x(1-\cos2x)}

=\dfrac{2\cos2x\sin^22x(1+\cos2x)}{\cos4x(1-\cos^22x)}=\dfrac{2\cos2x\sin^22x(1+\cos2x)}{\cos4x\sin^22x}=\dfrac{2\cos2x(1+\cos2x)}{\cos4x}

=\dfrac{4\cos2x\cos^2x}{\cos4x}

=\dfrac{4\cos2x\cos^2x\sin4x}{\cos4x\sin4x}=\dfrac{4\cos2x\cos^2x\tan4x}{\sin4x}

=\dfrac{4\cos2x\cos^2x\tan4x}{2\sin2x\cos2x}=\dfrac{2\cos^2x\tan4x}{\sin2x}

=\dfrac{2\cos^2x\tan4x}{2\sin x\cos x}=\dfrac{\cos x\tan4x}{\sin x}

=\dfrac{\tan4x}{\frac{\sin x}{\cos x}}=\dfrac{\tan4x}{\tan x}=\dfrac{\tan12A}{\tan3A}

QED

5 0
2 years ago
nadia was offered a job for selling ads cor a magazine. She must agree to one of the following paymen options. CHOICE A:$110 for
Fittoniya [83]

Let us say that:

x = is the number of ads that Nadia sold every week

P = payment or amount that she receives every week

 

So the equations we can formulate for choice A and B are:

choice A: P = 110 x

choice B: P = 150 + 85 x

 

The amount that she receives for A must be greater than she receives for choice B, so:

110 x > 150 + 85 x                       (inequality equation)

 

Calculate for x:

110 x – 85 x > 150

25 x > 150

x > 6

 

Therefore Nadia must sell more than 6 ads every week so that Choice A would be the better choice.

6 0
2 years ago
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