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ANTONII [103]
2 years ago
12

Sanjit drives the 45 km distance between York and Leeds he then drives a further 42 km from Leeds to Blackpool

Mathematics
2 answers:
arlik [135]2 years ago
8 0
45 km at 54 km/hr 

<span>45 / 54 = 5/6 </span>

<span>It took him 5/6 of an hour, or 50 minute </span>

<span>61.4117 km/hr </span>
I am Lyosha [343]2 years ago
3 0

Answer: His average speed for his total journey from York to Blackpool is approximately 61.41 km/h.

Step-by-step explanation:

\text{ The average speed}=\frac{\text{Total distance covered}}{\text{Total time taken}}

Since, The distance covered by him from York to Leeds = 45 km,

The speed when he covered this distance = 54 km/ h

Thus, the time taken by him in travelling from York to Leeds = 45/54 hours (Because, Time = Distance/speed)

Now, The distance covered by him from Leeds to Blackpool = 42 km,

The time taken by him in travelling from Leeds to Blackpool = 35 minutes = 35/60 hours

Hence, the total time taken by him in this journey

=\frac{45}{54}+\frac{35}{60}=\frac{450+315}{540}=\frac{765}{540}=\frac{17}{12} hours

And, the total distance he covered= 45 + 42 = 87 km

Thus, His average speed

=\frac{87}{17/12}= \frac{12\times 87}{17}=\frac{1044}{17}=61.4117647\approx 61.41\text{ km per hour}

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Step-by-step explanation:

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One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

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∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

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Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

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