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2 years ago

Which statement about proportional relationships is false?

Mathematics

2 answers:

maw [93]2 years ago

6 0

Answer:

Step-by-step explanation:

Got it right on quiz

777dan777 [17]2 years ago

4 0

Answer:

Each point (or pair) in a proportional relationship must share the same ratio.

Step-by-step explanation:

a proportional relationship must share the same ratio in order to be proportional it doesn't madder in what way it is proportional.

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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

2 years ago

The speed of a sparrow is x km/h in still air. When the

Semmy [17]

Answer:

x = 5m/s

Step-by-step explanation:

Distance flying out = 12 km (headwind)

Distance flying back = 12 km (tailwind)

total distance = 12 + 12 =24 km

wind speed = 1km/h

speed going out (with headwind) = (x - 1) km/h

speed coming back (with tailwind) = (x + 1) km/h

Time taken to go out = distance going out / speed going out

= 12 / (x-1)

Time taken to come back = distance coming back / speed coming back

= 12 / (x+1)

total time = time taken to go out + time taken to come back

5 =[ 12/(x-1) ] + [ 12/(x-1)]

expanding this, we will get

5x² - 24x - 5 = 0

solving quadratic equation, we will get

x = -1/5 (impossible because speed cannot be negative)

x = 5 (answer)

4 0

2 years ago

In a neighborhood, 2/5 of the houses are painted yellow. If there are 24 houses that are not painted yellow, how many yellow hou

grigory [225]

Answer:

There are 16 yellow houses in the neighborhood.

Step-by-step explanation:

We have that:

2/5 = 40% of the houses are painted yellow

1 - 2/5 = 3/5 = 60% of the houses are not painted yellow

If there are 24 houses that are not painted yellow, how many yellow houses are in the neighborhood?

The first step is finding the total number of houses in the neighborhood.

We have that 24 are not painted yellow, and this is 60%(0.6 decimal). How much is 100%?

We solve a rule of three

24 houses - 0.6

x houses - 1

$0.6x = 24$

$x = \frac{24}{0.6}$

$x = 40$

There are 40 houses. Of those, 40% are painted yellow.

0.4*40 = 16.

There are 16 yellow houses in the neighborhood.

7 0

2 years ago

Lola pulls two marbles from a bag containing four red marbles, four blue marbles, and 12 yellow marbles without replacing them.w

Degger [83]

It is the 2nd option. 0.13

5 0

2 years ago

Read 2 more answers

Simplify (5b)(-3a). -35ab -15ab 2ab

Fofino [41]

(5b)(-3a)
= (5*(-3))(b*a) (combine like terms)
= -15ab

The final answer is -15ab~

3 0

2 years ago

Read 2 more answers