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Zarrin [17]
1 year ago
8

Taylor bought 6 tickets to a movie. The price of each ticket was the same. After he bought the tickets, his account balance show

ed a change of −$68.04. What would have been the change to Taylor's account balance had he only bought 1 ticket to the movie?
answers -11.34 11.34 -11.40 11.40
Mathematics
1 answer:
Sladkaya [172]1 year ago
3 0

It is -11.34

-$68.04 divide by 6 is -$11.34, so instead of 11.34, it's -11.34

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If EBC = 31a - 2 and EBH = 4a + 45 find HBC
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Answer:

The measure of angle HBC is m∠HBC=61°

Step-by-step explanation:

In this problem we have that

The line BH bisects angle EBC,

see the attached figure to better understand the problem

then

m∠EBC=m∠EBH+m∠HBC

m∠EBH=m∠HBC

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m∠EBC=2(m∠EBH)

substitute the given values and solve for a

31a-2=2(4a+45)\\31a-2=8a+90\\31a-8a=92\\23a=92\\a=4

<em>Find the measure of angle EBH</em>

m∠EBH=(4(4)+45)=61°

Remember that

m∠EBH=m∠HBC

therefore

The measure of angle HBC is m∠HBC=61°

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The dimensions of the two different rectangular regions are;

1st Arrangement:

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2nd Arrangement:

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2nd Arrangement:

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Step-by-step explanation:

Bella is putting down patches of sod to start a new lawn.

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We are asked to provide the dimensions of two different rectangular regions that she can cover with the sod.

Recall that a rectangle has an area given by

Area = W*L

Where W is the width of the rectangle and and L is the length of the rectangle.

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20 = W*L

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Out of them, two different possible arrangements are;

1st Arrangement:

20 = (4)*(5) = (5)*(4)

Width is 4 yards and length is 5 yards or width is 5 yards and length is 4 yards

2nd Arrangement:

20 = (2)*(10) = (10)*(2)

Width is 2 yards and length is 10 yards or width is 10 yards and length is 2 yards

Therefore, the dimensions of two  different rectangular regions are;

1st Arrangement:

W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards

2nd Arrangement:

W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards

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P = 2(W + L)

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The perimeter of the 1st arrangement is

P₁ = 2(4 + 5)

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The perimeter of the 2nd arrangement is

P₂ = 2(2 + 10)

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So the perimeter of the 1st arrangement is 18 yards and the perimeter of the 2nd arrangement is 24 yards.

Note:

Another possible arrangement is,

20 = (1)*(20) = (20)*(1)

Width is 1 yard and length is 20 yards or width is 20 yards and length is 1 yard.

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