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zepelin [54]
2 years ago
8

At a gymnastics meet, three judges evaluate the balance beam performances of five gymnasts, using a scale from 1 to 10, where 10

is a perfect score. A statistician wants to see if the gymnasts (Factor A) differ in their performances and also wants to see if the scores vary significantly across judges (Factor B) in order to assess any bias in the judges. To do this the statistician uses a two-way ANOVA without interaction and the results are show below. At 0.05 level of significance, what is the critical value for testing differences in mean scores across the Gymnasts
Mathematics
1 answer:
Art [367]2 years ago
6 0

Answer:

As   2.551 < 3.84 therefore we reject H0.

As 44.803 > 4.46 so we accept null hypothesis.

Step-by-step explanation:

The answer is attached.

There are three judges so v1 = 3-1= 2  and v2 = (4*2)= 8

There are five gymnasts so v1 = 5-1= 4 and v2=  (4*2)= 8

For alpha = 0.05 we find the value of F1 and F2 from the table.

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A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro
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Step-by-step explanation:

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height of building= 30 meter

Now,

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Or W = W1 + W2

Work done in lifting the rope is given as,

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W1 = [0.2x²/2] at boundary of 30 and 0

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work done in lifting the sand is given as;

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F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

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Triangle $ABC$ has altitudes $\overline{AD},$ $\overline{BE},$ and $\overline{CF}.$ If $AD = 12,$ $BE = 14,$ and $CF$ is a posit
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Answer:

<u>CF = 7</u>

Step-by-step explanation:

Given: Δ ABC

Altitudes ⇒ AD = 12 , BE = 14  and  CF = ?

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OR area                          = 0.5 BE * AC  ⇒ (2)

OR area                          = 0.5 CF * AB  ⇒ (3)

By equating (1) and (3)

∴ 0.5 CF * AB = 0.5 AD * BC

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By equating (1) and (2)

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We should know that about the relation between the sides of the triangle:

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So, AB < BC + AC    ⇒ divide both sides by BC

∴ \frac{AB}{BC} < 1+\frac{AC}{BC}

By substitution from (5) with AC/BC

∴ \frac{AB}{BC}

∴ \frac{AB}{BC}

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By substitution from (6) at (4)

∴ CF > 12 * 7/13

CF > 6.46

But CF is a positive integer

<u>∴ CF = 7</u>

4 0
2 years ago
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