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Montano1993 [528]
1 year ago
15

A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro

pe that has a mass of 0.3 kg/m that must be secured to the bucket. It takes 1 meter of rope to secure the bucket. Once the bucket reaches the top of the building it only has mass 15 kg because there was a hole in the bottom and sand was leaking out at a constant rate while it was being lifted to the top of the building. Find the work done lifting the bucket (sand and rope) to the top of the building.
Mathematics
1 answer:
Rom4ik [11]1 year ago
5 0

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

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We have been given that all members of our painting team paint at the same rate. 20 members can paint a 6000 square foot wall in 24 minutes. We are asked to find the time taken by 20 members to paint 9000 square foot wall.

We will use proportions to solve our given problem.

\frac{\text{Time taken}}{\text{Area of wall painted}}=\frac{24\text{ min}}{6000\text{ ft}^2}

\frac{x}{9000\text{ ft}^2}=\frac{24\text{ min}}{6000\text{ ft}^2}

\frac{x}{9000\text{ ft}^2}\times 9000\text{ ft}^2=\frac{24\text{ min}}{6000\text{ ft}^2}\times 9000\text{ ft}^2

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Therefore, it will take 36 minutes for 20 members to paint 9000 square foot wall.

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The actual distance is 24 miles

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t​ Technodynamics, Inc., a​ randomly-selected hiring committee of 3 people is formed from a group of 4 employees in marketing an
atroni [7]

Answer: a) 0.25, b) 0.78, c) 0.71

Step-by-step explanation:

Since we have given that

Number of employees in marketing = 4

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We need to hire committee of 3 people.

​a) Find the probability that the committee has exactly 2 employees from marketing.

So, Probability becomes

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​b) Find the probability that the committee has at least one employee from marketing.

P(x\geq 1)=1-P(x=0)\\\\P(x\geq 1)=1-\dfrac{^7C_3}{^{11}C_3}=1-0.212=0.78

c) Find the probability that the committee has at most one employee from management.

P(x\leq 1)=P(x=0)+P(x=1)\\\\P(x\leq 1)=\dfrac{^7C_3}{^{11}C_3}+\dfrac{^7C_2\times ^4C_1}{^{11}C_3}\\\\P(x\leq 1)=0.21+0.50=0.71

Hence, a) 0.25, b) 0.78, c) 0.71

8 0
1 year ago
A square OABC with the length of a side 6 cm and circle k(O) with a radius 5 cm are given. Which of the lines OA , AB , BC , or
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Answer:

AC and OA

Step-by-step explanation:

-A secant is a  line connecting two points on the circle.

-Given the square OABC of sides 6cm and a circle of r=5cm and  the center of the circle as O, and that the radius of the circle is less than the side of the square:

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Hence, AC and OA are the circle's secants.

5 0
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1. Write an exponential function to represent the spread of Ben's social media post. 2. Write an exponential function to represe
Alex777 [14]

Answer:

1. y = 2(3)ˣ; 2. y = 10(4)^x; 4. Amber = 192 and 3 145 728;

Ben has 54 and 11 098; Carter = 80 and 10 249 shares;

5. Shifted up 45 shares; 6. Amber's;

7. Fewer friends. more shares.

Step-by-step explanation:

The general equation for an exponential function is

y = a(b)ˣ

1. Ben's function

The initial value a = 2.

6 = 2(b)¹ = 2b

Ben's function is  

y = 2(3)^x

2. Carter's function

Carter shared his post with 10 friends on Day 0, so  a= 10.  

Each friend shared with 2 people each day, so b = 2.

Therefore, Carter's function is

y=10(2)ˣ

3. Graphs

\begin{array}{cccc}& \textbf{Amber} &\textbf{Ben}  & \textbf{Carter}\\\mathbf{x} & \mathbf{3(4)^{x}} &\mathbf{2(3)^{x}} & \mathbf{10(2)^{x}}\\0 & 3 & 2 & 10\\1 & 12 & 6 & 20\\2 & 48 & 18 & 40\\3 & 192 & 54 & 80\\\end{array}

The figure below shows the graphs for each function.

4. Predictions

(a) Amber

(i) Day 3

y = 3(4)³  = 3 × 64 = 192

(ii) Day 10

y = 3(4)¹⁰  = 3 × 1 048 576 = 3 145 728

(b) Ben

(i) Day 3

y = 2(3)³  = 2 × 27 = 54

(ii) Day 10

y = 2(3)¹⁰  = 2 × 29 049 = 118 098

(c) Carter

(i) Day 3

y = 10(2)³  = 10 × 8 = 80

(ii) Day 10

y =10(2)¹⁰  = 10 × 1024 = 10 240

5. Sharing with assisted living facility

y = 3(4)ˣ + 45

The new graph will be shifted up by 45 units.

6. Fastest post

Amber's post travels the fastest.

After only two days, she already has more posts than anyone else.

By Day 10, she has more than 25 times the shares of her closest competitor.

7. Preference

It's not the number of friends you have, but the number of shares they make, that is the important factor.

Carter started with 10 friends, but they made only two shares.

Amber started with only three friends, but they made four shares. By Day 3, she had 192 shares compared to 82 for Carter and only 54 for Ben

If I had to choose, I would prefer a post with fewer friends initially but more shares, like Amber.

5 0
1 year ago
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