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SpyIntel [72]
2 years ago
11

Mr. Nguyen plants 24 trees around the neighborhood pond. he plants equal numbers of maple,pine,spruce, and birch trees. ge water

s the spruce and birch trees before it gets dark. how many trees dose Mr. Nguyen still need to water? draw and label a tape diagram
Mathematics
1 answer:
Goryan [66]2 years ago
5 0
Since he has 24 trees and 4 kinds of trees you divide them and get 6 that means there 6 trees in one kind so he already watered 2 kinds of trees and so you have 2 kinds of trees left so you do 6 × 2 = 12
the answer is 12
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Linda saves $1.55 every day. Tyron saves $3.90 every day. Linda started saving 3 days earlier than Tyron. On which day will Tyro
madreJ [45]
Step 1: Write the amount of savings in equation
Linda's savings: s=1.55d
Tyron's savings: m=3.90d

Step 2: Add on the extra days to Linda's savings
Linda's savings s=1.55d+3(1.55)

Step 4: Simplify equation
s=1.55d+3(1.55)
s=1.55d+4.66

Step 5: Substitute numbers for d days until Tyron's m savings is greater than Linda's s saving
m=3.90d s=1.55(2)+4.66
m=3.90(2) s=3.10+4.66
m=7.80 s=7.76

On Tyron's second day he will have more money in his savings than Linda does.
4 0
2 years ago
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Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
2 years ago
Read 2 more answers
Use the normal approximation to the binomial distribution to answer this question. Fifteen percent of all students at a large un
Nataly_w [17]

Answer: 0.1289

Step-by-step explanation:

Given : The proportion of all students at a large university are absent on Mondays. : p=0.15

Sample size : n=12

Mean : \mu=np=12\times0.15=1.8

Standard deviation = \sigma=\sqrt{np(1-p)}

\Rightarrow\ \sigma=\sqrt{12(0.15)(1-0.15)}=1.23693168769\approx1.2369

Let x be a binomial variable.

Using the standard normal distribution table ,

P(x=4)=P(x\leq4)-P(x\leq3)              (1)

Z score fro normal distribution:-

z=\dfrac{x-\mu}{\sigma}

For x=4

z=\dfrac{4-1.8}{1.2369}\approx1.78

For x=3

z=\dfrac{3-1.8}{1.2369}\approx0.97

Then , from (1)

P(x=4)=P(z\leq1.78)-P(z\leq0.97)\\\\=0.962462-0.8339768\approx0.1289    

Hence, the probability that four students are absent = 0.1289

3 0
2 years ago
Simplify!!! <br><br>I need help please ​
satela [25.4K]

Answer:

\frac{4^{21}}{5^{6}}

Step-by-step explanation:

\frac{4^{7*3}}{5^{2*3}}=\frac{4^{21}}{5^{6}}

3 0
2 years ago
Liz and Andy make money selling jewelry at a local fair. Liz and Andy both sell necklaces for $8 each. Andy also sells bracelets
Gelneren [198K]

Equation for Liz:

L = 8n

Equation for Andy:

A = 8n + 35

Step-by-step explanation:

Let the no. of necklace be 'n'

Cost per necklace= $8

Equation for Liz:

L = 8n

Because Liz sells only necklace for $8 each

Equation for Andy:

A = 8n + 35

Because Andy sells each necklace for $8 and she sold the bracelets for $35

7 0
2 years ago
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