Denote by M the point of intersection of the medians.
Denote also the distance DM by x and the distance QM by y.
From the median properties of triangles we know that

Also,

Since the medians are perpendicular, we deduce that:

Then, since
Answer:
16 degrees Celsius, with breaks at 172 degrees Fahrenheit.
Step-by-step explanation:
To calculate 86 degrees in Fahrenheit you need to take the 86 degrees you are given and first mulitply it by 5 over 9 (5/9). That will give you about 48 degrees. To finish solving it for celsius you then need to take your 48 and subtract 32, in which you would get 16. So, the temprature Tom needs to take a break at is 172 degrees Fahrenheit.
Answer:
P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)
Step-by-step explanation:
Here given that a basketball player that shoots 80% from the free throw line attempts two free throws.
If x is the no of shoots he makes (say) then we find that each throw is independent of the other.
In other words, because he made successful first attempt, his chances for second attempt will not change
Prob for success in each attempt remains the same as 0.80
Hence I throw is independent of II throw.
When A and B are independent,then we have
P(A/B) = P(A)
Hence answer is
P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)
First ask yourselfhat needs to be dristributed.
That would be -1 (x-9)
To distribute you have to multiply the number out side of the parentheses (-1) by each term inside the parentheses( x and -9)
-1×x=-x
-1×-9=9
Now the expression is
-x+9+4x
To simplify you have to combine like terms (4x and-x)
4x-x=3x
Your answer is 9+3x or 3(3+x).
IN finding the interest we need to use the following formula:
Interest= Principal x Rate x Time or I= PRT
Substitute values: I= [$20 + ($10 x $34)] -320 =$40
P= $320
R=?
T=10 months/year
I=PRT
Since R is a missing term, we will solve for R using this formula: R=I/PT
R= [<span>$20 + ($10 x $34)-320] / ($320 x 10 months)
T=10 months</span>÷12 months=0.83<span>
R= ($40)/ $320 X 0.83
R= 40/ 265.6
R=15.06024096</span>