Answer:
The amount of work required to remove all of the water by pumping it over the side = 3.12 × 10⁶ lbs.ft
Step-by-step explanation:
Work done in moving anything from point A to point B = Fx
For this setup,
If we take an elemental vertical height, dx, The volume would be A.dx
where A = Cross sectional Area = πr² = π(18)² = 1017.88 ft²
dV = 1017.88 dx
The elemental force on that part will be
dF = ρg dV
ρg = 63.8 lbs/ft³
dF = 63.8 × 1017.88 dx = 64940.5 dx
F = ∫dF = 64940.5 dx
W = Fx = (∫dF)x = ∫ 64940.5x dx = 64940.5 ∫ xdx
We'll be integrating from (11 - 6) ft to 11 ft because that's the total height it'll be pumped through
W = 64940.5 (x²/2)¹¹₅ = 64940.5((11² - 5²)/2) = 3.12 × 10⁶ lbs.ft
Answer:
150 short sleeves ordered
100 long sleeves ordered
Answer:
144 gold bars
Step-by-step explanation:
first you fine the area gold bars take up in cubic inches by multiplying the 3, 2, and 6 to get 36
once you have the space 1 gold bar takes up you divide the total space by that the total space is 5184 so you divide 5184 by 36 to get 144
