Answer: f(x) = (x + 3)(x – 7)
Step-by-step explanation: Use "standard form" of the function and insert values given: vertex (2,-25) intercept point (7,0)
f(x) = a(x-h)² + k from vertex, h is 2 y is -25 from intercept, x is 7 f(x) is 0
to find a, 0 = a(7-2)² +(-25) 0 = a(7-2)² -25 add 25 to both sides
25 = a(5)² 25 = 25a 25/25 = a 1=a (seems useless but verifies implied "a"coefficient is 1)
f(x) = a(x-h)² + k solve to get the quadratic form
f(x) = (x-2)² -25 (x - 2)² is x² -4x +4
f(x) = x² -4x +4 -25 simplify
f(x) = x² -4x - 21 then factor
f(x) = (x + 3)(x - 7)
Answer:
What is the probability that you will finish this quiz in 23.84 minutes or less?
0.03593
Write your answer as a percentage with 2 decimals
= 3.59%
Step-by-step explanation:
The z score formula is given as:
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Mean = 26 minutes
Standard deviation = 1.2 minutes.
The probability that you will finish this quiz in 23.84 minutes or less(≤) is calculated as:
z = (x-μ)/σ
z = 23.84 - 26/1.2
z = -1.8
Probability value from Z-Table:
P(x ≤ 23.84) = 0.03593
Converting to percentage
0.03593 × 100
= 3.593
Approximately to 2 decimal places = 3.59%
Answer:
7% = $34
100% = 100/7 X 34 = 3400/7 = $ 485.71 OR $ 486 ANSWER.
Step-by-step explanation:
100% = 100/7 X 34 = 3400/7 = $ 485.71 OR $ 486 ANSWER.
Answer: (-2)(4)
Step-by-step explanation:
The model could be explained as follows ;
Step 1 : 0 - - - - > - 2 = - 2 units
Step 2 : -2 - - - - > -4 = - 2 units
Step 3: - 4 - - - - > -6 = - 2 units
Step 4: - 6 - - - - > -8 = - 2 units
-2 units for reach of the 4 steps
Therefore, model is expressed as :
(-2) × 4
(-2)(4)
Kindly view detailed sketch and explanation in the picture attached.
Answer:
Step-by-step explanation:
The graph is a nonlinear graph.
The hang time is 3 seconds.
The h- coordinate of the top of the bump is about 11 m, so the maximum height is 11 m after rounding to the nearest meter.
For t between 0 and 1.5, the height is increasing.
I hope this helps. I found it on Khan Academy.
