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kykrilka [37]
2 years ago
9

Complete the steps to find all zeroes of the function f(x) = x4 − 4x3 − 4x2 + 36x − 45. This function has roots.

Mathematics
2 answers:
xxTIMURxx [149]2 years ago
7 0
Steps?

A graph shows zeros to be ±3. Factoring those out leaves the quadratic
  (x-2)² +1
which has complex roots 2±i.

The function has roots -3, 3, 2-i, 2+i.

lapo4ka [179]2 years ago
5 0

this function has 4 roots.

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A store receives shipments of peaches and wants to sort them by weight. Drag each shipment to match the ratio of peaches to poun
Andrej [43]

Answer:


Step-by-step explanation:

Given that a store receives shipments of peaches.  They want to sort them by weight.

The sorting pattern is as follows:

Peaches : Pound = 2:1 or 3.25:1 or 1:3.25

Given are i) 26 peaches to 13 lbs = 26:13=2:1 Hence goes to the first box

ii) 6 peaches to 19.5 lbs =6:19,5 = 1:3,25 lb. Hence goes to II box

iii) 13 peaches to 4 lbs: =13:4=3.25:1   Hence goes to II box

iv) 39 peaches to 12 lbs: =39:12=3.25:1   Hence goes to II box

v) 15 peaches to 7.5 lbs: =15:7.5=2:1   Hence goes to I box

i    - I box

ii   -  II box

iii   - II box

iv) -   II box

v) - I box

8 0
2 years ago
Two random samples are taken from private and public universities
kati45 [8]

Answer:

Step-by-step explanation:

For private Institutions,

n = 20

Mean, x1 = (43120 + 28190 + 34490 + 20893 + 42984 + 34750 + 44897 + 32198 + 18432 + 33981 + 29498 + 31980 + 22764 + 54190 + 37756 + 30129 + 33980 + 47909 + 32200 + 38120)/20 = 34623.05

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (43120 - 34623.05)^2+ (28190 - 34623.05)^2 + (34490 - 34623.05)^2 + (20893 - 34623.05)^2 + (42984 - 34623.05)^2 + (34750 - 34623.05)^2 + (44897 - 34623.05)^2 + (32198 - 34623.05)^2 + (18432 - 34623.05)^2 + (33981 - 34623.05)^2 + (29498 - 34623.05)^2 + (31980 - 34623.05)^2 + (22764 - 34623.05)^2 + (54190 - 34623.05)^2 + (37756 - 34623.05)^2 + (30129 - 34623.05)^2 + (33980 - 34623.05)^2 + (47909 - 34623.05)^2 + (32200 - 34623.05)^2 + (38120 - 34623.05)^2 = 1527829234.95

Standard deviation = √(1527829234.95/20

s1 = 8740.22

For public Institutions,

n = 20

Mean, x2 = (25469 + 19450 + 18347 + 28560 + 32592 + 21871 + 24120 + 27450 + 29100 + 21870 + 22650 + 29143 + 25379 + 23450 + 23871 + 28745 + 30120 + 21190 + 21540 + 26346)/20 = 25063.15

Summation(x - mean)² = (25469 - 25063.15)^2+ (19450 - 25063.15)^2 + (18347 - 25063.15)^2 + (28560 - 25063.15)^2 + (32592 - 25063.15)^2 + (21871 - 25063.15)^2 + (24120 - 25063.15)^2 + (27450 - 25063.15)^2 + (29100 - 25063.15)^2 + (21870 - 25063.15)^2 + (22650 - 25063.15)^2 + (29143 - 25063.15)^2 + (25379 - 25063.15)^2 + (23450 - 25063.15)^2 + (23871 - 25063.15)^2 + (28745 - 25063.15)^2 + (30120 - 25063.15)^2 + (21190 - 25063.15)^2 + (21540 - 25063.15)^2 + (26346 - 25063.15)^2 = 1527829234.95

Standard deviation = √(283738188.55/20

s2 = 3766.55

This is a test of 2 independent groups. Let μ1 be the mean out-of-state tuition for private institutions and μ2 be the mean out-of-state tuition for public institutions.

The random variable is μ1 - μ2 = difference in the mean out-of-state tuition for private institutions and the mean out-of-state tuition for public institutions.

We would set up the hypothesis. The correct option is

-B. H0: μ1 = μ2 ; H1: μ1 > μ2

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (34623.05 - 25063.15)/√(8740.22²/20 + 3766.55²/20)

t = 9559.9/2128.12528473889

t = 4.49

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8740.22²/20 + 3766.55²/20]²/[(1/20 - 1)(8740.22²/20)² + (1/20 - 1)(3766.55²/20)²] = 20511091253953.727/794331719568.7114

df = 26

We would determine the probability value from the t test calculator. It becomes

p value = 0.000065

Since alpha, 0.01 > than the p value, 0.000065, then we would reject the null hypothesis. Therefore, at 1% significance level, the mean out-of-state tuition for private institutions is statistically significantly higher than public institutions.

4 0
1 year ago
ABCDEFGHIJ is a regular decagon. It rotates clockwise about its center to form the polygon A′B′C′D′E′F′G′H′I′J′. Match each angl
Lostsunrise [7]
A decagon has 10 sides.

It it is regular you can build 10 isosceles triangles from the center of the decagon to the 10 sides.

Each triangle has a common vertex where the angle of each triangle is 360° / 10 = 36°.

So each time that you rotate the decagon a multiple of 36° around the center you get an image that coincides with the original decagon.

If the letters are given clockwise:

- when you rotate 36° counter clockwise, the point A' (the image of A) will coincide with the point J.

- when you rotate 72° (2 times 36°) counter clockwise, the point A' will land on I.

- when you rotate 108° (3 times 36°) counter clockwise, the point A' will land on H.

- when you rotate 144° (4 times 36°) counter clockwise, the point A' will land on G.

- when you rotate 180° (5 times 36°) counter clockwise, the point A' will land on I.

- when you rotate 216° (6 times 36°) counter clockwise, the point A' will land on E.

- whn you rotate 252° (7 times 36°) counterclockwise, the point A' will coincide with D.

Add other 36° each time and A' will coincide successively with C, B and the same A.
8 0
1 year ago
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Step-by-step explanation:

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Step-by-step explanation:

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