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evablogger [386]
2 years ago
11

Carson is a high school student with two part-time jobs. He earns $6 per hour for babysitting, and he earns $8 per hour doing cl

erical work for his father's business. His goal is to earn at least $96 a week, but because of school, he does not want to work more than 15 hours each week. ​ Part A Let b represent the number of hours Carson works in one week at the babysitting job, and let c represent the number of hours Carson works in one week at his father's business. Which inequalities represent the constraints on what Carson can earn and the number of hours he can work in one week? Select all that apply.​ A b+c≤15 B 6b+8c≤15 C 6b+8c≥15 D b+c≥96 E 6b+8c≥96 F 6b+8c≤96 Part B Which combination of number of hours would allow Carson to work 15 hours in one week and earn at least $96? Select all that apply. A 10 hours babysitting and 5 hours clerical B 11 hours babysitting and 4 hours clerical C 12 hours babysitting and 3 hours clerical D 13 hours babysitting and 2 hours clerical E 14 hours babysitting and 1hour clerical Part C Suppose Carson worked as a babysitter for 5 hours one week. What is the minimum number of full hours he would need to work at his father's business to earn at least $96 that week? ​Enter your answer in the box. ​ hours ​ ​ ​ Part D ​Suppose Carson worked at his father's business for hours one week. What is the minimum number of full hours he would need to babysit that week to earn at least that week? ​​Enter your answer in the box.

Mathematics
2 answers:
pickupchik [31]2 years ago
7 0

Answer:

Step-by-step explanation:

maksim [4K]2 years ago
6 0

Answer:

Part A: A, E Part B: A, B, C Part C: 8 hours Part D: 5 hours

Step-by-step explanation:

Part A:

hours that he works (b and c) should be less than or equal to (\leq \\) 15

Option A

amount of money he makes for each (6b and 8c) should be greater than or equal to (\geq) 96

Option E

Part B:

Amount he makes should be greater than or equal to 96

Option A 6(10)+8(5)=100

Option B 6(11)+8(4)=98

Option C 6(12)+8(3)=96

Part C:

6(5)=30

96-30=66

66÷8=8.25

Part D:

8(8)=64

96-64=32

32÷6=5.33

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1) Proiectiile catetelor unui triunghi dreptunghic pe ipotenuza au lungimile 9 cm si 25 cm. Aflati lungimea inaltimii din varful
Flauer [41]

Answer:

1) 15cm

2) left projection/h = h/right projection

Step-by-step explanation:

Question:

1) The projections of the legs of a right triangle on the hypotenuse have lengths of 9 cm and 25 cm. Find the length of the height at the top of the right angle.

2) In a right triangle the length of the hypotenuse is 34 cm, and the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75. Calculate the length of the height corresponding to the hypotenuse.

Solution

1) The length of the height of a right angle triangle is also called the altitude.

Since there are no diagrams in the question, I sent a diagram of the right angle as an attachment to the solution.

The projections of the legs are 25cm and 9cm.

Hence, the longer projection length AD = 25cm and the shorter projection length DB = 9cm

In a right triangle, the altitude (height) drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the

geometric mean of these two segments (the two projections) and it's given by:

left projection/h = h/right projection

AD/h = h/DB

25/h = h/9

Cross multiply

h^2 = 25×9

h =√225 = 15cm

The length of the height at the top of the triangle = 15cm

2) Length of hypotenuse = 34

From the question, the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75.

There is an error with the figures because the sum of the length of the projection of the legs should be equal to the hypotenuse but it isn't in this case.

To calculate the length of the height corresponding to the hypotenuse, we would use the same formula above.

left projection/h = h/right projection

To find each leg using question 1 above, each leg of the triangle is the mean proportional between the hypotenuse and the part of the hypotenuse directly below the leg.

Hypotenuse =34cm

Hyp/leg = leg/part

To find leg y, part for leg y = 25cm

34/y = y/25

y^2 = 34×25 = 850

y = √850 = 29.2cm

To find leg x, part for leg x = 9cm

34/y = y/9

y^2 = 34×9 = 306

y = √306 = 17.5cm

8 0
2 years ago
you ride your bike to a store, 4 miles away, to pick up things for dinner. when there is no wind, you ride at 10 mi/h. today you
Tresset [83]
4 miles= (10-s) x 1hr. S could stand for the speed of the wind, since it is taking away from the typical speed of the bike.
3 0
1 year ago
Which of the following slopes show that the set of points C(1, 1), D(3, -4), E(5, 8) are not collinear?
MArishka [77]
C is the answer you want

8 0
2 years ago
Read 2 more answers
Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did
vladimir1956 [14]

Mukat gets 40, Usha gets 8

Step-by-step explanation:

Mukat = 5 × Usha

After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)

Then Mukat = final number of books for Usha

5 × Usha - 16 = Usha + 16

(5 × Usha ) - Usha = 16+16

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Usha = 8 i.e her number of books.

Mukat = 5×8=40.

I HOPE IT'S OK

6 0
2 years ago
Which measure is the largest? 1.2 km, 120,600 cm, 1,220,000 mm, 120 meters
aalyn [17]
The answer would be 1,220,000mm.

You can do this if you convert all the measures into one unit. Let us convert all into km. 

The first one is already in km, so we do not need to covert it. 

Let's start with converting 1,220,000mm to km. 


There are 1, 000,000 mm in one km. 

1,220,000X \frac{1km}{1,000,000mm} = 1.22km

So there are 1.22km 
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Next, we have 120m. There are 1,000m in 1km.

120mX \frac{1km}{1,000} =0.12km

There are 0.12km in 120m

Now you can see that 1,220,000mm is the longest. 


4 0
2 years ago
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