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evablogger [386]
2 years ago
11

Carson is a high school student with two part-time jobs. He earns $6 per hour for babysitting, and he earns $8 per hour doing cl

erical work for his father's business. His goal is to earn at least $96 a week, but because of school, he does not want to work more than 15 hours each week. ​ Part A Let b represent the number of hours Carson works in one week at the babysitting job, and let c represent the number of hours Carson works in one week at his father's business. Which inequalities represent the constraints on what Carson can earn and the number of hours he can work in one week? Select all that apply.​ A b+c≤15 B 6b+8c≤15 C 6b+8c≥15 D b+c≥96 E 6b+8c≥96 F 6b+8c≤96 Part B Which combination of number of hours would allow Carson to work 15 hours in one week and earn at least $96? Select all that apply. A 10 hours babysitting and 5 hours clerical B 11 hours babysitting and 4 hours clerical C 12 hours babysitting and 3 hours clerical D 13 hours babysitting and 2 hours clerical E 14 hours babysitting and 1hour clerical Part C Suppose Carson worked as a babysitter for 5 hours one week. What is the minimum number of full hours he would need to work at his father's business to earn at least $96 that week? ​Enter your answer in the box. ​ hours ​ ​ ​ Part D ​Suppose Carson worked at his father's business for hours one week. What is the minimum number of full hours he would need to babysit that week to earn at least that week? ​​Enter your answer in the box.

Mathematics
2 answers:
pickupchik [31]2 years ago
7 0

Answer:

Step-by-step explanation:

maksim [4K]2 years ago
6 0

Answer:

Part A: A, E Part B: A, B, C Part C: 8 hours Part D: 5 hours

Step-by-step explanation:

Part A:

hours that he works (b and c) should be less than or equal to (\leq \\) 15

Option A

amount of money he makes for each (6b and 8c) should be greater than or equal to (\geq) 96

Option E

Part B:

Amount he makes should be greater than or equal to 96

Option A 6(10)+8(5)=100

Option B 6(11)+8(4)=98

Option C 6(12)+8(3)=96

Part C:

6(5)=30

96-30=66

66÷8=8.25

Part D:

8(8)=64

96-64=32

32÷6=5.33

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Answer: The children weighing 10 pounds, 15 pounds and 30 pounds require 12 teaspoons , 18 teaspoons, 36 teaspoons respectively.

Step-by-step explanation:

Given, The recommended dosage is 40 milligrams per 2.2 pounds of body weight, divided into three daily doses and taken every 8 hours.

i.e. for 1 pound of body weight required dosage per day= \dfrac{40}{2.2}=18.18\ ml

Each dose consist = \dfrac{18.18}{3}=6.06\ ml drug.

so, 1 pound of body weight required 6.06 ml for each dose.

Then, 10 pounds of body weight require 10 x 6.06 ml drug= 60.6 ml

If 1 teaspoon = 5 ml,  then 10 pounds of body weight require (60.6 ml ÷5) = 12.12 ≈12 teaspoons.

15 pounds of body weight require 15 x 6.06 ml drug= 90.9 ml

Then 15 pounds of body weight require (90.9 ml ÷5) = 18.18≈18 teaspoons.

30 pounds of body weight require  30 x 6.06 ml drug= 181.8 ml

Then  30 pounds of body weight require (181.8 ml ÷5) = 36.36 ≈ 36 teaspoons.

Hence, the children weighing 10 pounds, 15 pounds and 30 pounds require 12 teaspoons , 18 teaspoons, 36 teaspoons respectively.

7 0
2 years ago
The Answer is 8 for, "The product of 32 and an unknown number subtracted from 435 is 179.
nirvana33 [79]
Putting this into an equation looks like this:

435 - 32<em>x</em> = 179

-32<em>x</em> = -256

<em>x</em> = 8


The answer <em>is</em> 8. Well done.
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2 years ago
The table below shows the amount paid for different numbers of items. Determine if this relationship forms a direct variation. V
Elden [556K]
<h2>Answer/Step-by-step explanation:</h2>

Direct variation occurs when a variable varies directly with another variable. That is, as the x-variable increases, the y-variable also increases.

The ratio of between y-variable and x-variable would be constant.

Direct variation can be represented by the equation, y = xk, where k is a constant. Thus,

\frac{y}{x} = k

From the table given, it seems, as x increases, y also increases. Let's find out if there is a constant of proportionality (k).

Thus, ratio of y to x, \frac{0.50}{1} = 0.5

k = 0.5.

If the given table of values has a direct variation relationship, then, plugging in the values of any (x, y), into \frac{y}{x} = k, should give us the same constant if proportionality.

Let's check:

When x = 2, and y = 1:

\frac{y}{x} = k,

\frac{1}{2} = 0.5,

When x = 3, y = 1.5:

\frac{1.5}{3} = 0.5,

When x = 5, y = 2.50:

\frac{2.5}{5} = 0.5,

The constant of proportionality is the same. Therefore, the relationship forms a direct variation.

5 0
2 years ago
The aquarium has 10 more red fish than blue fish. 60 percent of the fish are red. How many blue fish are in the aquarium?
guajiro [1.7K]

Answer:

20 blue fish

Step-by-step explanation:

Number of blue fish = x

Number of red fish = x+10

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Total fish = x+x+10 = 2x+10

0.6 = (x+10)/(2x+10)

Solve for x:

1.2x+6 = x+10

0.2x = 4

x = 20

Hope this helps!

Mark as brainliest :))

7 0
2 years ago
Read 2 more answers
Use forward and backward difference approximations of O(h) and a centered difference approximation of O(h2) to estimate the firs
strojnjashka [21]

Answer:

Answer has explained below.

Step-by-step explanation:

Consider the function is:

F(x) = 25x3 – 6x2 +7x -88

Differentiate with respect to x, we get

F’(x) = 25. 3x2 – 6.2x + 7

       = 75x2 – 12x +7

At x = 2, we have

F (2) = 25(2)3 – 6(2)2 + 7(2)-88

        =102

And f’(2) = 75(2)2 – 12 (2) +7

               =283

Now, calculate forward divided difference as:

xi + 1 = xi + h

        =2 + 0.25

        =2.25

F (xi + 1) = f (2.25) = 25 (2.25)3 – 6(2.25)2 +7(2.25) -88

                            =182.21

f’(2) = f(2.25) – f(2) / 0.25 = 182.21 – 102 / 0.25

                                             = 320.84

Єt = 283 – 320.8 / 283 = -13.36%

Now calculate backward divided difference:

Xi-1 = xi –h = 2 – 0.25 = 1.75

F(xi-1)= f(1.8) = 25 . (1.8)3 -6 (1.8)2 + 7 (1.8) – 88

                       = 50.96

F’(2) = f(2) – f(1.8) / 0.25 = 102 – 50.96 / 0.25 = 204.16

Єt = 283 – 204.16 / 283 = 27.86%

Finally, centered divided difference is obtain by inserting f(xi+1) and f (xi-1):

F’(2) = f(2.25) – f(1.8) /2 x 0.25 = 320.84 -50.96 / 0.5 = 539.68

Єt = 283 – 539.68 / 283 = -90.7%

6 0
2 years ago
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