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Kitty [74]
2 years ago
14

Pam served her apple pie on a 13 inch diameter dish. She wanted to tie a ribbon around the dish to make it a little more festive

. How long does the ribbon need to be in order to fit around the dish
Mathematics
2 answers:
zlopas [31]2 years ago
8 0

Answer:

Length of ribbon = 40.86 inches

Step-by-step explanation:

Length of the ribbon = circumference of the dish = πD

D = diameter = 13 inches

Length of ribbon = 22/7 x 13 = 40.857143 inches

kenny6666 [7]2 years ago
8 0

Answer:

40.9 inches

Step-by-step explanation:

The question say that:

Pam served her apple pie on a 13 inch diameter dish. She wanted to tie a ribbon around the dish to make it a little more festive. How long does the ribbon need to be in order to fit around the dish

First and foremost, we need to know what this question is all about.

The dish is obviously a circle in terms of its shape and the dish has a diameter of of 13 inch.

The circumference of a circle is 2 pi × radius

And we all know that how long a circle is it's circumference.

Diameter is twice of a radius so if the diameter is 13 inch,then the radius will be 13/2 = 6.5 inch

Circumference = 2× 22/7 × 6.5 = 40.857 inches.

Therefore,the length of the ribbon to be tied round the plate is 40.9 inches.

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Will a 7/32 inch diameter pin fit into a reamed hole with a diameter of 0.215 inches?
lana [24]

Answer:

no ... the pin will not fit the reamed hole

Step-by-step explanation:

The decimal equivalent of 7/32 is 0.21875.  This is larger than the reamed

hole:                                                  0.215

and so the answer is no ... the pin will not fit the reamed hole.

6 0
2 years ago
Money Spent on Road Repair A politician wishes to compare the variances of the amount of money spent for road repair in two diff
Mkey [24]

Answer:

(A) Null Hypothesis, H_0 : \sigma_1^{2} =\sigma_2^{2}      {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, H_A : \sigma_1^{2} \neq \sigma_2^{2}      {means that there is a significant difference in the variances of the amounts spent in the two counties}

(B) The F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) The value of the F-test statistic is 0.611.

(D) We conclude that there is no significant difference in the variances of the amounts spent in the two counties.

Step-by-step explanation:

We are given that a politician wishes to compare the variances of the amount of money spent on road repair in two different counties.

The data are given here below;

County A              County B

s1 = $11,596         s2 = $14,837

n1 = 15                     n2 = 18

Let \sigma_1^{2} = variances of the amounts spent in County A.

\sigma_2^{2} = variances of the amounts spent in County B.

(A) So, Null Hypothesis, H_0 : \sigma_1^{2} =\sigma_2^{2}      {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, H_A : \sigma_1^{2} \neq \sigma_2^{2}      {means that there is a significant difference in the variances of the amounts spent in the two counties}

The test statistics that would be used here <u>Two-sample F-test statistics </u>distribution;

                             T.S. =  \frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }  ~ F__n_1_-_1,_ n_2_-_1

where, s_1 = sample standard deviation for County A = $11,596

s_2 = sample standard deviation for County B = $14,837

n_1 = sample size for County A = 15

n_2 =  sample size for County B = 18

(B) Now at 0.05 level of significance, the F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) So, <u><em>the test statistics</em></u>  =  \frac{11,596^{2}  }{14,837^{2} } \times 1  ~  F__1_4,_ 1_7

                                     =  0.611

The value of the F-test statistic is 0.611.

Now, as we can see that our test statistics lie within the range of critical values of F, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

(D) Therefore, we conclude that there is no significant difference in the variances of the amounts spent in the two counties.

7 0
2 years ago
Which equation represents the line that passes through (–6, 7) and (–3, 6)? y = –y equals negative StartFraction one-third EndFr
DiKsa [7]

Answer:

y=-\frac{1}{3} x+5

Step-by-step explanation:

Notice that the answers they give you to choose from are all lines in slope y-intercept form, it would be very simple to just find the answer finding yourself the slope and y-intercept of the line in question.

Since they give you two points (x_1,y_1) and  (x_2,y_2) for the line, use them to find the slope of the line that goes through them, with the formula:  slope=\frac{y_2-y_1}{x_2-x_1} =\frac{7-6}{-6-(-3)} =\frac{1}{-3} =-\frac{1}{3}

Therefore, the slope of the line must be -\frac{1}{3}

Now, find the y-intercept (b) using the general form of a line with the given slope:

y=-\frac{1}{3}x +b

Use one of the given coordinate points to request that the line passes through it. For example, through the point (-3,6) (when x = -3, y must be 6):

y=-\frac{1}{3} x+b\\6=-\frac{1}{3}(-3)+b\\6=1+b\\b=6-1=5

then the y-intercept must be 5. Therefore our line is : y=-\frac{1}{3}x +5 which appears listed as your second choice.

8 0
2 years ago
Read 2 more answers
A restaurant served 25,000 customers in 2012. In 2014, the restaurant served 26,600 customers. Write a linear model that represe
DerKrebs [107]

Answer:


Step-by-step explanation:

y=25000(1+6,4%)^x

x=8 (2012-2020)

3 0
2 years ago
Read 2 more answers
Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea
asambeis [7]

Answer:

n\geq 23

Step-by-step explanation:

-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:

n\geq (\frac{z\sigma}{ME})^2

Where:

  • \sigma is the standard deviation
  • ME is the desired margin of error.

We substitute our given values to calculate the sample size:

n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23

Hence, the smallest desired sample size is 23

3 0
2 years ago
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