Answer:
2.1/√55
Step-by-step explanation:
simga divided by sample size
as far as I can tell, is just a matter of going around the circle many or infinite times around.
so 6,31° is the first point, the next point will be one-go-around, 6, 31+360 => 6, 391°
then the next will be 6, 391+360 => 6, 751° and so on.
so we can say is (6, 31° ±360°n), n ∈ ℤ.
Answer:

Step-by-step explanation:
Given:
°
From the triangle, using the theorem that center angle by an arc is twice the angle it subtend at the circumference.

Also, the diameter of the circle is BD. As per the theorem that says that angle subtended by the diameter at the circumference is always 90°,

From the Δ BCD, which is a right angled triangle,

Now, using the theorem that angle between the tangent and a chord is equal to the angle subtended by the same chord at the circumference.
Here, chords CD and BC subtend angles 40 and 50 at the circumference as shown in the diagram by angles
and EF is a tangent to the circle at point C.
Therefore, 
Again, using the same theorem as above,

Hence, all the angles are as follows:

Answer
given,
thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
X = U[0.95,1.05] 0.95≤ x ≤ 1.05
the cumulative distribution function of flange
F(x) = P{X≤ x}=
=
b) P(X>1.02)= 1 - P(X≤1.02)
= 
= 0.3
c) The thickness greater than 0.96 exceeded by 90% of the flanges.
d) mean = 
= 1
variance = 
= 0.000833
Answer:
0.00
Step-by-step explanation:
If the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are normally distributed, to calculate the probability that a test taker scores at least 1600 on the test, we should first to calculate the z-score related to 1600. This z-score is
, then, we are seeking P(Z > 2.95), where Z is normally distributed with mean 0 and standard deviation 1. Therefore, P(Z > 2.95) = 0.00