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Dafna11 [192]
2 years ago
10

Which congruence theorem can be used to prove △WXS ≅ △YZS? Triangles W X S and Y Z S are connected at point S. Angles W X S and

S Z Y are right angles. Sides X S and S Z are congruent. SSS ASA SAS HL
Mathematics
2 answers:
sergejj [24]2 years ago
6 0

Answer:

ASA

Step-by-step explanation:

iVinArrow [24]2 years ago
3 0

Point S makes the two connected angles the same. They both have right angles.

And one side of each is congruent.

This means you know 2 angles are the same and one side is the same.

You would use ASA (Angle, Side, Angle)

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When graphing the inequality y ≤ 2x − 4, the boundary line needs to be graphed first. Which graph correctly shows the boundary l
Aleksandr [31]

The answer is B.) 2nd. Picture

4 0
2 years ago
A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of
babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization \gamma(t) = (10\cos t, 10 \sin t, 90-5t)

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by \frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5). The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}

d) ON the same fashion we want to know the norm of the second derivative of \gamma.

We have that \gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0) so the acceleration is given by \sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10 

6 0
1 year ago
Lucy has to run two errands. She starts from home and travels 3 miles south to the post office. From the post office, she travel
alexira [117]

Answer:

the correct choice is A. At the gas station

Step-by-step explanation:

Lucy starts at home and travels 3 miles south to the post office. From the post office, she travels 4 miles east to the gas station. As it is known south and east directions form right angle. Since the entire trip forms a triangle, this triangle is right with right angle at the post office.

Call the vertices of this triangle P - post office, G - gas station, H - home. Then HP and PG are legs of this triangle and GH is hypotenuse.

From the given data:

HP=3;

PG=4;

GH=5;

∠P=90°.

The smallest angle is opposite to the smallest side. The smallest side is leg HP, so the smallest angle is G that is the angle at gas station.

6 0
1 year ago
Read 2 more answers
What is the sum of the distinct prime factors of 315
Nuetrik [128]

Answer: The exponents in the prime factorization are 2, 1, and 1. Adding one to each and multiplying we get (2 + 1)(1 + 1)(1 + 1) = 3 x 2 x 2 = 12. Therefore 315 has exactly 12 factors.

Step-by-step explanation: First, the exponents in the prime factorization are 2, 1, and 1. Then adding one to each and multiplying we get (2 + 1)(1 + 1)(1 + 1) = 3 x 2 x 2 = 12. Finally, 315 has exactly 12 factors.

7 0
1 year ago
Fiona wrote the linear equation y = x – 5. When Henry wrote his equation, they discovered that his equation had all the same sol
Oliga [24]
His equation could be written in quadratic form, which is ax^2+bx=c                     


7 0
1 year ago
Read 2 more answers
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