Answer:
1) 2/7
2) 8/11
3) 3/2 or 1 1/2
4) 32/35
Step-by-step explanation:
1.5/7•14/35
= 5/7 × 14/35
Using Cancellation method
= 1/1 × 2/7
= 2/7
2.[4/5][10/11]
= 4/5 × 10/11
Using Cancellation method
= 4/1 × 2/11
= 8/11
3.8 3/4 multiplied by 2/9
= 8 3/4 × 2/9
= 27/4 × 2/9
= 3/2 × 1/1
= 3/2
= 1 1/2
4. [4/5]10/11][7/8]
40/50 ÷ 77/88
= 40/50 × 88/77
= 40/50 × 8/7
= 40/25 × 4/7
= 8/5 × 4/7
= 32/35
Answer:
your answer is a and d
Step-by-step explanation:
To solve this problem, we need to know that
arc length = r θ where θ is the central angle in radians.
We're given
r = 6 (units)
length of minor arc AB = 4pi
so we need to calculate the central angle, θ
Rearrange equation at the beginning,
θ = (arc length) / r = 4pi / 6 = 2pi /3
Answer: the central angle is 2pi/3 radians, or (2pi/3)*(180/pi) degrees = 120 degrees
Answer:
1.692 m/min
Step-by-step explanation:
Let 
be the angle between the two sides and x be the length of the third side. By cosine rule,
We differentiate x with respect to by applying chain rule.
Rate of change of is 2
Rate of change of x is
At 60°,
Answer:
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
Step-by-step explanation:
(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)
(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)
−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3
−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3
