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Drupady [299]
1 year ago
11

Solve (Y+5)^3/2=4 where y is a real number

Mathematics
1 answer:
koban [17]1 year ago
5 0

Answer:

y {}^{2}  + 10y =  - 33.5

Step-by-step explanation:

(y+5)(y+5)x3/2=4

Y(y+5)+5(y+5) x 3/2=4

y {}^{2}  + 5y + 5y + 25 \times 3  \2 = 4

y ^{2}  + 10y + 75 \2 = 4

y {}^{2}  + 10y + 37.5 = 4

y {}^{2}  + 10y = 4 - 37.5

y {}^{2}  + 10y =  - 33.5

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How many leap years occur between the<br> years 1700 and 1875?
Zina [86]

Step-by-step explanation:

A leap year occurs every 4th year.

So, 1875 - 1700 = 175

Now let us divide 175 by 4

175 \div 4 = 43.75 \\  here \: 43 \: represents \: the \: number \: of \:  \\ leap \: years.

So, 43 leap years occur between the years 1700 and 1875.

6 0
2 years ago
A matrix contains 60 elements. Which of the following cannot equal the number of rows of the matrix?
avanturin [10]

<span>Given:

Matrix = 60 elements</span>

 

<span>To solve this, we need to take into account that each row must contain the same number of elements. So, we need to find which of the options do not divide evenly into 60 (the options are 30, 60, 10, and 18).

So we check each of the choices to see if 1 of them divides evenly with 60.

60 / 60 = 1 (divides evenly)</span>

60 / 30 = 2 (divides evenly)

<span>60 / 10 = 6 (divides evenly)
</span>60 / 18 = 3.3.3333333333333333333333333333333 (does not divide evenly)

Therefore, 18 cannot equal the number of rows of the matrix.

6 0
2 years ago
Kelly, Laura, and Tia so boxes of cookies for a fundraiser. Kelly sold 15 boxes less than Laura. Tia so twice as many boxes as K
Andre45 [30]

Answer:

Laura 32

Kelly 17 )

Tia 34  

Step-by-step explanation:

L+ (L-15)  + 2(L-15) = 83

4L - 45 = 83

4 L = 128

L =  32    

Laura 32

Kelly 17 (32-15)

Tia 34  (2*17)

32+17+34 = 83

7 0
2 years ago
Read 2 more answers
El producto de dos números consecutivos es 552 cuáles son esos números?
lara31 [8.8K]

Answer: 23 y 24 ( ó -23 y -24)

Step-by-step explanation:

Dos números consecutivos se escriben como:

n y (n + 1)

done n es un numero entero.

Entonces "El producto de dos números consecutivos es 552"

Se escribe como:

n*(n + 1) = 552

n^2 + n = 552

n^2 + n - 552 = 0

Tenemos una cuadrática, las posibles soluciones son obtenidas con la formula de Bhaskara.

n = \frac{-1 +- \sqrt{1^2 - 4*1*(-552)} }{2} = \frac{-1 +- 47}{2}

Las dos soluciones son.

n = (-1 - 47)/2 = -48/2 = -24

n = (-1 + 47)/2 = 46/2 = 23

Si tomamos la primer solución, n = -24

Entonces los dos números consecutivos son:

n = -24

(n + 1) = -23

Si n = 23 entonces

n + 1 = 24

Lo cual tiene sentido, por que lo único que cambia son los signos, los cuales se cancelarían en la multiplicación.

7 0
2 years ago
kabir spends 1/3of his pocket money on books,1/5on traveling and rest on food.if his pocket money is 450 rupees how much money d
Talja [164]

Answer:

210

Step-by-step explanation:

450 X 1/3 = 150

450 X 1/5 = 90

.

90 + 150 = 240

.

450 - 240 = 210

4 0
2 years ago
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