1 year ago

Solve (Y+5)^3/2=4 where y is a real number

Mathematics

1 answer:

koban [17]1 year ago

5 0

Answer:

$y {}^{2} + 10y = - 33.5$

Step-by-step explanation:

(y+5)(y+5)x3/2=4

Y(y+5)+5(y+5) x 3/2=4

$y {}^{2} + 5y + 5y + 25 \times 3 \2 = 4$

$y ^{2} + 10y + 75 \2 = 4$

$y {}^{2} + 10y + 37.5 = 4$

$y {}^{2} + 10y = 4 - 37.5$

$y {}^{2} + 10y = - 33.5$

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Given that a piece of ribbon is cut into two shorter pieces in the ratio 2.8:1.25.

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