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1 year ago

11

Solve (Y+5)^3/2=4 where y is a real number

1 answer:

koban [17]1 year ago

5 0

Answer:

$y {}^{2} + 10y = - 33.5$

Step-by-step explanation:

(y+5)(y+5)x3/2=4

Y(y+5)+5(y+5) x 3/2=4

$y {}^{2} + 5y + 5y + 25 \times 3 \2 = 4$

$y ^{2} + 10y + 75 \2 = 4$

$y {}^{2} + 10y + 37.5 = 4$

$y {}^{2} + 10y = 4 - 37.5$

$y {}^{2} + 10y = - 33.5$

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Step-by-step explanation:

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If the area of the rectangle is given by the polynomial 2x^2-7x-15, what is the dimension of the reactangle in terms of x?

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Answer:

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Step-by-step explanation:

<h3>Given</h3>

Area of rectangle = 2x^2 - 7x - 15

<h3>To find</h3>

Dimensions of rectangle

<h3>Solution</h3>

<u>Since the area is the product of the sides, let's try to factorize the given:</u>

2x^2 - 7x - 15=
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2x(x - 5) + 3(x - 5) =
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<u>So the dimensions are:</u>

x - 5 and 2x + 3

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