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Drupady [299]
1 year ago
11

Solve (Y+5)^3/2=4 where y is a real number

Mathematics
1 answer:
koban [17]1 year ago
5 0

Answer:

y {}^{2}  + 10y =  - 33.5

Step-by-step explanation:

(y+5)(y+5)x3/2=4

Y(y+5)+5(y+5) x 3/2=4

y {}^{2}  + 5y + 5y + 25 \times 3  \2 = 4

y ^{2}  + 10y + 75 \2 = 4

y {}^{2}  + 10y + 37.5 = 4

y {}^{2}  + 10y = 4 - 37.5

y {}^{2}  + 10y =  - 33.5

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Answer:

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