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Drupady [299]
1 year ago
11

Solve (Y+5)^3/2=4 where y is a real number

Mathematics
1 answer:
koban [17]1 year ago
5 0

Answer:

y {}^{2}  + 10y =  - 33.5

Step-by-step explanation:

(y+5)(y+5)x3/2=4

Y(y+5)+5(y+5) x 3/2=4

y {}^{2}  + 5y + 5y + 25 \times 3  \2 = 4

y ^{2}  + 10y + 75 \2 = 4

y {}^{2}  + 10y + 37.5 = 4

y {}^{2}  + 10y = 4 - 37.5

y {}^{2}  + 10y =  - 33.5

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pashok25 [27]
9×2=18. add the tow zeros like this 9×2=18+00=1,800
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Which of the following is NOT true when testing a claim about a​ proportion? Choose the correct answer below. A. Both the tradit
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Answer: C. A conclusion based on a confidence interval estimate will be the same as a conclusion based on a hypothesis test.

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To write a null hypothesis, first, start by asking a question. Rephrase that question in a form that assumes no relationship between the variables. In other words, assume a treatment has no effect. Write your hypothesis in a way that reflects this.

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2 years ago
Use the binomial theorem to find the coefficient of xayb in the expansion of (5x2 + 2y3)6, where a) a = 6, b = 9. b) a = 2, b = 15.
goldfiish [28.3K]

Answer:

Step-by-step explanation:

                    1

                1      1

            1      2      1

         1     3      3      1

      1    4     6       4       1

   1   5    10     10       5     1

 1    6   15   20      15    6     1

1    6   15   20      15    6     1

we use these for the expansion of (5x² + 2y³)⁶

1(5x²)⁶(2y³)⁰ + 6(5x²)⁵(2y³)¹ + 15(5x²)⁴(2y³)² + 20(5x²)³(2y³)³+  15(5x²)²(2y³)⁴+ 6(5x²)¹(2y³)⁵ + 1(5x²)⁰(2y³)⁶

78125ₓ¹²+187500ₓ¹⁰ y³ +37500ₓ⁸y⁶+20000ₓ⁶y⁹+6000x⁴y¹²+960x²y¹⁵+2y¹⁸

a.)a = 6, b = 9. the coefficient of xᵃyᵇ ( 20000ₓ⁶y⁹) = 20000

b) a = 2, b = 15. the coefficient of xᵃyᵇ ( 960x²y¹⁵) = 960

c) a = 3, b = 12. the coefficient of xᵃyᵇ is not present

d) a = 12, b = 0 the coefficient of xᵃyᵇ ( 78125ₓ¹²)  = 78125

e) a = 8, b = 9. the coefficient of xᵃyᵇ is not present

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2 years ago
Cora is playing a game that involves flipping three coins at once. Let the random variable HHH be the number of coins that land
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Answer:

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P(H<3) = 0.125 + 0.375 + 0.375

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If you have more than one group of something, you will have more than what you started with.
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