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77julia77 [94]
2 years ago
15

Sample Response: His work is not correct. You first must switch x and y and then solve for y.

Mathematics
2 answers:
Firlakuza [10]2 years ago
6 0
If you are using edgenuity click all of them and you’ll be counted correct. I am not trolling you just have to trust me
yuradex [85]2 years ago
3 0

Answer:

click all of them

Step-by-step explanation:

have a wonderful day stay safe :)

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Eight less than four times a number is less than 56. What are the possible values of that number
yan [13]
Let unknown number be x.

Given,

4x - 8 < 56

4x < 64

x < 16

Hence, x is any value less than 16.
4 0
1 year ago
Read 2 more answers
a university theater sold 556 tickets for a play, tickets cost $22 per adult tickets and $ 12 for senior citizen ticket, if the
Deffense [45]
Let no. of adult tickets be x and senior citizen tickets be y. x + y = 556 22x + 12y = 8492 Solving by simultanous equations, x = 182 adult tickets y = 374 senior citizen tickets
7 0
2 years ago
Carlton Hinkler offered $179,900 for a home that had been priced at $210,500. The seller agreed to the offer. If he made a $36,0
katovenus [111]

Answer

The answer will be 66600

P.S i hope i'm right i am only in 5th grade and i do not know if this is adding and subtracting

5 0
2 years ago
Which statements about the box plot are correct? Check all that apply.
Rudiy27

Answer:

The correct options are 1 and 3.

Step-by-step explanation:

From the given box plot it is clear that

\text{Minimum values}=34

Q_1=42

Q₁ is 25% of a data.

Median=46

Median is 50% of a data.

Q_3=70

Q₃ is 75% of a data.

\text{Maximum values}=76

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.

42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.

The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.

Hence option 3 is correct.

The interquartile range of the data is

IQR=Q_3-Q_1

IQR=70-42=28

The interquartile range is 28. Therefore option 4 is incorrect.

Range of the data is

Range=Maximum-Minimum

Range=76-34=42

The range is 42. Therefore option 5 is incorrect.

3 0
1 year ago
Read 2 more answers
Find the balance in the account. $800 principal earning 7%, compounded annually, after 4 years
scoray [572]
800×(1.07)^(4) =1,048.63
6 0
2 years ago
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