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miskamm [114]
2 years ago
11

Fran graphs the equations y = 2x2 – 2 and y = –0.5x + 4. Her graph is shown below. mc010-1.jpg Which value is an approximate sol

ution of 2x2 – 2 = –0.5x + 4?

Mathematics
2 answers:
r-ruslan [8.4K]2 years ago
5 0

Answer:

x = -2 is an approximate solution of 2x2 – 2 = –0.5x + 4.

Step-by-step explanation:

miv72 [106K]2 years ago
3 0
On the added picture you can see that graphs of functions y=2x^2-2 and y=-0.5x+4 have two points of intersection. The x-coordinates of these points are the solutions of the equation 
2x^2-2=-0.5x+4.
Hence, the approximate solutions are x=-1.9 and x=1.6.


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The amount of time required to reach a customer service representative has a huge impact on customer satisfaction. Below is the
Vika [28.1K]

Answer:

The value of the test statistic is t=1.12.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the mean amount of time required to reach a customer service representative significantly differs between the two hotels.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0

The sample 1, of size n1=20 has a mean of 2.65 and a standard deviation of √2.952=1.72.

The sample 2, of size n2=20 has a mean of 2.01 and a standard deviation of √2.952=1.89.

The difference between sample means is Md=0.64.

M_d=M_1-M_2=2.65-2.01=0.64

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{1.72^2+1.89^2}{20}}\\\\\\s_{M_d}=\sqrt{\dfrac{6.531}{20}}=\sqrt{0.327}=0.571

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.64-0}{0.571}=\dfrac{0.64}{0.571}=1.12

5 0
2 years ago
Every day, a lecture may be canceled due to inclement weather with probability 0.05. Class cancelations on different days are in
andrezito [222]
<h3>(a)Probability of cancelling at least 4 classes  is 0.0055.</h3><h3>(b)Probability of 10th class is third class that gets cancelled  = 0.0031</h3>

Step-by-step explanation:

Here, the question is<u> incomplete</u>.

Every day, a lecture may be canceled due to inclement weather with probability 0.05. Class cancellations on different days are independent.

(a) There are 15 classes left this semester. Compute the probability that at least 4 of them get canceled.

(b) Compute the probability that the tenth class this semester is the third class that gets canceled.

Now, here:

The probability of cancelling each class  = 0.05

Now, probability of cancelling at least 4 classes

= 1 - P(Cancelling  at max 3 classes)

=  1 - P(0 ≤ x  ≤  3)   = 1 - Binomial (15,0.05,3)

= 0.0055

Hence, probability of cancelling at least 4 classes  is 0.0055.

(b) As given, 10th class is third class that gets cancelled.

So, the first and second classes that get cancelled in between 1 - 9.

P(2 class cancelled in 1st 9) = Binomial (15,0.05,3) = 0.0629

Also, as given  P(10th class cancelled) = 0.05

⇒ P(10th class is third class that gets cancelled ) = 0.0629 x 0.05 = 0.0031

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2 years ago
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Answer:

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Step-by-step explanation:

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T.J. invests $8,100 in an account
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Answer:

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Step-by-step explanation:

Compound Interest Formula

A=P(1+\frac{r}{n} )^{nt}

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r = interest rate

n = number of times the rate is applied during a time period

t = number of times the time period has elapsed

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6 0
2 years ago
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