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shepuryov [24]
2 years ago
8

George tells you that when variables are in the denominator, the equation four over five plus three over x equals one over two b

ecomes unsolvable. George explains, "There is a value for x that makes the denominator zero, and you can't divide by zero." Demonstrate to George how the equation is still solvable and explain your reasoning.
Mathematics
2 answers:
hoa [83]2 years ago
6 0

Answer:

Step-by-step explanation:

The equation is still solvable and the denominator will not become zero as:

Consider the given equation,

\frac{4}{5}+\frac{3}{x}=\frac{1}{2}

⇒\frac{3}{x}=\frac{1}{2}-\frac{4}{5}

⇒\frac{3}{x}=\frac{5-8}{10}

⇒\frac{3}{x}=\frac{-3}{10}

⇒-3x=10{\times}3

⇒-3x=30

⇒x=-10

jeka57 [31]2 years ago
3 0
<span><span><u>Answer</u>
This explanation shows that the equation is solvable and there is not where in the steps we get a zero on the denominator.


</span><span><u>Explanation</u>
</span><span>The equation given in the statement is;
4/5+3/x=1/2
This equation can be solved as follows:
4/5+3/x=1/2
3/x=1/2-4/5=(5-8)/10
3/x= -3/10
Taking the reciprocal on both side of the equation;
x/3=-10/3
Multiplying by 3 both sides we get;
</span><span>x= -10
</span></span>
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Answer:

y-\frac{1}{3}=\frac{3}{4}(x-4)              

Step-by-step explanation:              

we know that            

The equation of the line into point slope form is equal to                        

y-y1=m(x-x1)              

In this problem we have          

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substitute the given values                

y-\frac{1}{3}=\frac{3}{4}(x-4)

therefore

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The mean of a normally distributed group of weekly incomes of a large group of executives is $1,000 and the standard deviation i
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Answer:

The z-score (value of z) for an income of $1,100 is 1.

Step-by-step explanation:

We are given that the mean of a normally distributed group of weekly incomes of a large group of executives is $1,000 and the standard deviation is $100.

<em>Let X = group of weekly incomes of a large group of executives</em>

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The z-score probability distribution for a normal distribution is given by;

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where, \mu = mean income = $1,000

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The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, we are given an income of $1,100 for which we have to find the z-score (value of z);

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