Question

Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthesis.) and has a slope of StartFraction 3 Over 4 EndFraction.? y – y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis. = y minus StartFraction 3 Over 4 EndFraction equals StartFraction one-third EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4) y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4) y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = 4(x – ) y – 4 = y minus 4 equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus StartFraction one-third EndFraction right-parenthesis.(x – )

Answer 1

Answer:

$y-\frac{1}{3}=\frac{3}{4}(x-4)$              

Step-by-step explanation:              

we know that            

The equation of the line into point slope form is equal to                        

$y-y1=m(x-x1)$              

In this problem we have          

$(x_1,y_1)=(4,\frac{1}{3})$                            

$m=\frac{3}{4}$            

substitute the given values                

$y-\frac{1}{3}=\frac{3}{4}(x-4)$

therefore

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

             

Answer 2

Answer:

The answer is y-1/3 = 3/4(x-4)

Step-by-step explanation:

Simple