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2 years ago

How would u find 4 1\5 divided by 2 1\3

2 answers:

4 0

4 1/5=21/5
2 1/3=7/3

so you take 21/5 divided by 7/3 and you change the division to a multiplication and invert the second fraction and solve 21/5*3/7.

the answer is 49/5 (simplify it to 9 4/5)

Over [174]2 years ago

3 0

Remmber
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
conver to improper

4 and 1/5=20/5+1/5=21/5
2 and 1/3=6/3+1/3=7/3

(21/5)/(7/3)=(21/5)(3/7)=63/35=9/5=1 and 4/5

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The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is five times

rusak2 [61]

Answer:

$x=30\\y=68\\z=82$

Step-by-step explanation:

x = measure of the first angle

y = measure of the second angle

z = measure of the third angle

The sum of the measures of the second and third (y+z) is five times the measure of the first angle (=5x)

$y+z=5x$

The third angle is 14 more than the second

$z=y+14$

And remember that the sum of these three angles must be equal to 180.

$x+y+z=180$

Let's take these equations

$y+z=5x\\z=y+14\\x+y+z=180$

If you take a look at the first equation, we have y+z = 5x and we have y+z in the third equation as well, we can replace that....

$x+y+z=180\\x+(y+z)=180\\x+(5x)=180$

Distribute the + sign

$x+5x=180$

Combine like terms;

$6x=180$

Divide by 6.

$x=\frac{180}{6}\\ x=30$

We have now defined that the measure of the first angle is 30º.

Let's take another equation... for example $z=y+14$

I'm going to take this one because if I replace x and z in the third equation, all I'll have left will be y.

$x+y+z=180\\30+y+(y+14)=180$

Distribute the + sign and Combine like terms;

$30+y+y+14=180\\44+2y=180\\$

Subtract 44 to isolate 2y.

$2y=180-44\\2y=136$

Now divide by 2.

$y=\frac{136}{2}\\ y=68$

We already have the value of x and y. Once again, replacing this in the third equation will leave us with z to solve for.

$x+y+z=180\\30+68+z=180\\98+z=180\\z=180-98\\z=82$

5 0

2 years ago

Solve for the indicated variable u=x-k, for x

Papessa [141]

X = u + k
hope this helps & hope I get the brainliest answer

6 0

2 years ago

Read 2 more answers

Jing spent 1/3 of her money on a pack of pens, 1/2 of her money on a pack of markers, and 1/8 of her money on a pack of pencils.

Reika [66]

As per the problem

Jing spent $\frac{1}{3}$ of her money on a pack of pens.

$\frac{1}{2}$ of her money on a pack of markers.

and $\frac{1}{8}$ of her money on a pack of pencils.

Total fraction of money spent cab be given as below

Fraction of Money Spent = $\frac{1}{3} +\frac{1}{2}+\frac{1}{8}$

Take the LCD of denominator, we get LCD of (3,2,8)=24

Fraction of Money Spent = $\frac{8+12+3}{24} =\frac{23}{24} \\\\$

$\\ \text{Hence fraction of Money Spent }=\frac{23}{24} \\ \\ \text{Fraction of Money left}=1-\frac{23}{24} \\ \\ \text{Simplify, we get}\\ \\ \text{Fraction of Money left}=\frac{24-23}{24} \\ \\ \text{Fraction of Money left}=\frac{1}{24}$