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2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −2y2 + 6y = −2

2 answers:

8 0

-2y^2 + 6y + 2 = 0
a = -2, b = 6, c = 2
x = (- b + - sqrt(b^2-4ac))/(2a)
x=(-6+-sqrt(36-4*-2*2))/-4
x=(-6+-sqrt(36+16))/-4
x=(-6+-sqrt(52))/-4
x = (-6 +- 2sqrt13)/-4
x = (3 + - sqrt13)/2

Anarel [89]2 years ago

7 0

Answer:

-0.3 Or 3.3

Step-by-step explanation:

-2y^2 + 6y + 2 = 0

X = -6 + 7.21/-4 or -7 - 7.21/-4

X = -0.3 or X = 3.3

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A bookstore owner has 48 science fiction books and 30 mysteries he wants to sell quickly. He will make discount packages with on

Nuetrik [128]

Answer:

the science fiction books and five mystery books in each package. This is because 6 is the highest common factor of both 48 and 30, and 6 x 8 = 48 and 6 x 5 = 30.

7 0

2 years ago

Read 2 more answers

N 2004, the General Social Survey (which uses a method similar to simple random sampling) asked, "Do you consider yourself athle

zmey [24]

Answer-

The standard error of the confidence interval is 0.63%

Solution-

Given,

n = 2373 (sample size)

x = 255 (number of people who bought)

The mean of the sample M will be,

$M=\frac{x}{n} =\frac{255}{2373} =0.1075$

Then the standard error SE will be,

$SE=\sqrt{\frac{M\times (1-M)}{n}}$

$SE=\sqrt{\frac{0.1075\times (1-0.1075)}{2373}}=\sqrt{\frac{0.0959}{2373}}=0.0063=0.63\%$

Therefore, the standard error of the confidence interval is 0.63%

6 0

2 years ago

Using the midpoint method, find the cross-price elasticity of demand for FedEx and UPS overnight shipping if the price of FedEx

IrinaK [193]

Answer:

Cross price elasticity using midpoint method = 0.56

Step-by-step explanation:

Using the mid-point method

Cross-price Elasticity of Demand = % change in Quantity demanded of UPS

% change of price of FedEx

%change in Quantity demanded of UPS

using Mid-point method = Q2-Q1 × 100

(Q1+Q2)÷ 2

= 1.3-1.2 × 100

(1.2+1.3)÷2

= 0.1 × 100

1.25

= 8%

% change in price of FedEx

using midpoint method = P2-P1 × 100

(P1+P2)÷ 2

= 75-65 × 100

(65+75)÷2

= 10 × 100

= 14.28%

Cross-price Elasticity of Demand = 8% ÷ 14.28%

using midpoint method = 0.56

6 0

2 years ago

the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev

Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 16, \sigma = 2.1$