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2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth. −2y2 + 6y = −2

2 answers:

8 0

-2y^2 + 6y + 2 = 0
a = -2, b = 6, c = 2
x = (- b + - sqrt(b^2-4ac))/(2a)
x=(-6+-sqrt(36-4*-2*2))/-4
x=(-6+-sqrt(36+16))/-4
x=(-6+-sqrt(52))/-4
x = (-6 +- 2sqrt13)/-4
x = (3 + - sqrt13)/2

Anarel [89]2 years ago

7 0

Answer:

-0.3 Or 3.3

Step-by-step explanation:

-2y^2 + 6y + 2 = 0

X = -6 + 7.21/-4 or -7 - 7.21/-4

X = -0.3 or X = 3.3

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Step-by-step explanation:

The equation given is $\frac{2x^{4} + 7x^{3} + 18x^{2} + 11x -2}{2x^{2} - 3x + 1 }$

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