Three classes of school children are selling tickets to the school play. the number of tickets sold by these classes, and the nu
2 answers:
We know that by employing the formula for the average here, we can find the average number of tickets sold per school child as the ratio of the total number of tickets sold to the total number of children in the school.
Let A be the average number of tickets sold per school child.
Let T be the total number of tickets sold.
Let C be the total number of children in the school.
Then from the information provided in the question,
T=tickets1+tickets2+tickets3 and C=class1+class2+class3
Thus, A can be expressed as:
The above is the expression for the average number of tickets sold per school child.
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Answer:
Step-by-step explanation:
Let, the number of cans collected by Shane = x.
So, the number of cans collected by Abha = x + 178.
Since, at least 2000 cans are required to be collected.
Thus, we have the inequality,
Number of cans by Shane + Number of cans by Abha ≥ 2000.
i.e.
i.e.
Thus, the required inequality is .
Answer:
I think your functions are ,
and
If yes then then the third function which is .
Step-by-step explanation:
The function where c is a constant has
Domain :
Range : ( 0 , ∞ )
The above range is irrespective of the value of c.
I have attached the graph of each of the function, you can look at it for visualization.
- <em>
⇒ </em>This function is same as
so its range is <em>( 0 , ∞ )</em>.
- <em>
⇒ </em>If we double each value of the function
, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as <em>( 0 , ∞ )</em>.
- <em>
</em> ⇒ If we add 2 to each value of the function
Total number of tables in the cafeteria = 20
65% of the tables =
= 13
Each table has 6 chairs.
So, total number of chairs that 65% of the tables have = 13 × 6 = 78.
35% of the tables =
= 7
Each table has 4 chairs.
So, total number of chairs that the remaining 35% of the tables have = 7 × 4 = 28.
Hence, total number of chairs in the hospital cafeteria = 78 + 28 = 106.