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muminat
2 years ago
9

Pecans that cost $28.50 per kilogram were mixed with almonds that cost $22.25 per kilogram. How many kilograms of each were used

to make a 25 kilogram mixture costing $24.25 per kilogram? Show all work
Mathematics
1 answer:
atroni [7]2 years ago
5 0

Answer:

The pecans used in the mixture =  8 kg

The almonds used in the mixture  =  17 kg

Step-by-step explanation:

The cost of per kg of pecans  = $28.50

The cost of per kg of almonds = $22.25

Now, total weight of mixture  = 25 kg

Let us assume the weight of pecans in the mixture   =   m kg

So, the amount of almonds in the mixture  = Total weight - Weight of Pecans

= (25 - m) kg

Now, cost of m kg pecans  = m x ( cost of 1 kg pecans) = m x ( $ 28.50)

                                              =  28.50 m

cost of (25- m) kg almonds  = (25 -m)  x ( cost of 1 kg almonds)

                                                = (25 - m) x ( $ 22.25)

                                                =  556.25  - 22.25 m

Total cost  of 25 kg of mixture  = 25 x ( $24.25) =  $606.25

Now, Total Cost of (almonds  + Pecans)  = Total cost of mixture

⇒28.50 m + 556.25  - 22.25 m  = $606.25

or,6.25 m =  50

or, m = 50/6.25 =  8

Hence, the pecans used in the mixture = m = 8 kg

And the  almonds used in the mixture  = (25 - m) = 25 - 8 = 17 kg

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all work is pictured/shown

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2 years ago
Consider a sample with a mean of 500 and a standard deviation of 100. What are the z-scores for the following data values: 560,
julsineya [31]

Answer:

z-score for value 560 = 0.6

z-score for value 650 = 1.5

z-score for value 500 = 0

z-score for value 450 = -0.5

z-score for value 300 = -2

Step-by-step explanation:

We are given a sample with a mean of 500 and a standard deviation of 100.

i.e., \mu = 500 and \sigma = 100

The z score distribution is given by;

              Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where X represents the data values;

  • So, z score for value 560 is;

                 z score = \frac{560-500}{100} = 0.6

  • So, z score for value 650 is;

                 z score = \frac{650-500}{100} = 1.5

  • So, z score for value 500 is;

                 z score = \frac{500-500}{100} = 0

  • So, z score for value 450 is;

                 z score = \frac{450-500}{100} = -0.5

  • So, z score for value 300 is;

                 z score = \frac{300-500}{100} = -2

7 0
2 years ago
At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a
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Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

a)

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

b)

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

3 0
2 years ago
*PLEASE ANSWER ASAP* John is playing a game with two friends. Using the spinner pictured, one friend spun a three, and the other
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Answer:

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5 0
2 years ago
Loretta’s income last year was $81,300. She made $56,800 at her salaried job and had additional passive income. If Loretta earne
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Answer:

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Step-by-step explanation:

step 1

To find out the amount of the additional passive income last year, subtract the amount earned at her salaried job from Loretta’s income last year

so

\$81,300-\$56,800=\$24,500

step 2

Divide the additional passive income last year by 12 (number of months in a year)

\$24,500/12=\$2,041.67

therefore

approximately $2,400 per month

5 0
2 years ago
Read 2 more answers
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