Given:
To find:
The highest and lowest scores Sam could have made in the tournament.
Solution:
We have,
It can be written as
Add 288 on both sides.
and
and
Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.
Answer:
<h3>Pudge has 12 morethan apples that is 24 apples and both Ace and Christi has not more than 12 apples together they has atmost 12 apples.The apples does each having is</h3><h3>P = Pudge's Apples =24</h3><h3>A = Ace's Apples =8</h3><h3>and C = Christi's Apples=4.</h3>Step-by-step explanation:
Let P = Pudge's Apples
Let A = Ace's Apples
Let C = Christi's Apples
<h3>To find how many apples does each have if Pudge has 12 more than both Ace and Christi together:</h3>Given that P = 3A , A = 2C and P = A + C + 12
Substitute the value for P in P = A + C + 12 we get
3A = A + C + 12
3A-A=C+12
2A=C+12
From A = 2C we have that
Substitute the value C:
Substituting the value of A in P=3A we get
P = 3(8)
<h3>∴ P = 24 </h3>Substituting the values of P and A in P = A + C + 12
4=C
Rewritting we get
<h3>∴ C=4 </h3><h3>Hence Pudge has 12 morethan apples that is 24 apples </h3><h3>and both Ace and Christi has not more than 12 apples together they has atmost 12 apples</h3>