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Pie
2 years ago
10

An element with mass 730 grams decays by 28.8% per minute. How much of the element is remaining after 10 minutes, to the nearest

10th of a gram?
Mathematics
2 answers:
Lana71 [14]2 years ago
8 0

Answer:

A= 24.4 grams

Step-by-step explanation:

An element with mass 730 grams decays by 28.8% per minute

For exponential decay we use formula

A= P(1-r)^t

Where P is the initial amount of element present

A is the amount remaining

r is the decay rate

and t is the time period in minutes

P= 730 grams, r= 28.8%= 28.8/100= 0.288, t= 10 minutes

A= 730(1-0.288)^10

A=24.44122

Round to nearest tenth

So A= 24.4 grams

trasher [3.6K]2 years ago
6 0
\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &730\\
r=rate\to 28.8\%\to \frac{28.8}{100}\to &0.288\\
t=\textit{elapsed time}\to &10\\
\end{cases}
\\\\\\
A=730(1-0.288)^{10}\implies A=730(0.712)^{10}
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Answer:

see explanation

Step-by-step explanation:

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Answer:

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