1 file -> 12 sheets
Now for 3 files -> 3*12 = 36 sheets, it takes up 2/3 of the total
So the total number of sheets: 36 / (2/3) = 54
X + y = 24...y = 24 - x
3.50x + 5.00y = 97.50
3.50x + 5(24 - x) = 97.50
3.50x + 120 - 5x = 97.50
3.50x - 5x = 97.50 - 120
-1.5x = -22.50
x = -22.50/-1.5
x = 15....there were 15 ten oz boxes (x) sold
Answer:
i doing the same problem like this, i was too lazy to do it but since there is no answer on the internet, here you are :
High category : 58%
Medium category : 61.0%
Step-by-step explanation:
Explain : like i said, i have a same question :D
we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
Answer:
i think it might be a or c
Step-by-step explanation:
because 12 =3