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xz_007 [3.2K]
2 years ago
9

Devon wants to write an equation for a line that passes through 2 of the data points he has collected. The points are (8, 5) and

(–12, –9). He writes the equation 7x – 10y = 3. Is this a good model? Explain your reasoning.
Mathematics
3 answers:
ser-zykov [4K]2 years ago
4 0
For this case we have the following equation:
 7x - 10y = 3

 From here, we must substitute ordered pairs of the form:
 (x, y)
 If the ordered pair satisfies the equation, then it belongs to the line.
 We have then:

 For (8, 5):
 
We substitute the following values:
 x = 8

y = 5

7 (8) - 10 (5) = 3

56 - 50 = 3

6 = 3
 We observe that the equation is not satisfied and therefore, this point does not belong to the line.
 Since one of the points does not belong to the line, then the equation is not a good model.

 Answer:
 
It is not a good model. One of the points does not belong to the line.
choli [55]2 years ago
4 0

no.....because when u sub in ur points (8,5) does not work and (-12,-9) does not work. He should have used this : 7x - 10y = 6

Guest1 year ago
0 0

Sample Response: If the model is good, then both points will check in the equation. Substituting 8 for x and 5 for y in the equation results in 56 – 50 = 3, which is not true. Therefore, the model is not good. Using (–12, –9) as a check results in –84 + 90 = 3. The constant value in the equation should be 6, not 3. In slope-intercept form, the y-intercept should be –3/5.

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) Lucy, Soling, Kyan, and Daniel are ordering dinner for their families. Each person spends
melisa1 [442]

Answer:

Lucy is 5(m+3)=65

Soling is 5m-3=65

Kyan is 5m+3=65

Daniel is 5(m-3)=65

Step-by-step explanation:

3 0
2 years ago
[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6
viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

              (b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

                  Height (in inches) of a 25 year old man is a normal random variable with mean g=71 and variance o^{2} =6.25.

To find:  (a) What percentage of 25 year old men are 6 feet, 2 inches tall

               (b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X>74in]

                           P[X>74] = P[\frac{X-g}{o} > \frac{74-71}{2.5}]

                                         = P[Z > 1.2]

                                         = 1 - P[Z ≤ 1.2]

                                         = 1 - Ф (1.2)

                                         = 1 - 0.8849

                                         = 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, 6ft 5in - X, 6ft]

     P[X > 6ft 5in I X > 6ft] = P[X > 77 I X > 72]

                                          = \frac{P[X > 77]}{P[ X > 72]}

                                          = \frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}]  }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }

                                          = \frac{P[Z >2.4]}{P[Z>0.4]}

                                          =  \frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }

                                          = \frac{1-0.9918}{1-0.6554}

                                          = \frac{0.0082}{0.3446}

                                          = 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0
2 years ago
Point F is on circle C. What is the length of line segment GF? 12.5 units 15.0 units 17.5 units 20.0 units
geniusboy [140]
The answer:
According to the image, <span>the length of line segment GF can be found with
</span>GF= GC +CF
CF is one the radius, so CF=7.5
to find GC, we can apply Pythagorean theorem on the right triangle GEC
it is 
GC² =GE² + EC² = 10² +7.5² =156.25, and then GC= sqrt(156.25)=12.5

therefore, GF= GC +CF=12.5+7.5=20

so the answer is <span>20.0 units</span>
7 0
2 years ago
A principal of $2000 is placed in a savings account at 3% per annum compounded annually. How much is in the account after one ye
natita [175]

Answer:

Step-by-step explanation:

After one year

A=p(1+r/n)^nt

=2000(1+0.03/12)^12*1

=2000(1+0.0025)^12

=2000(1.0025)^12

=2000(1.0304)

=$2060.8

After two-years

A=p(1+r/n)^nt

=2060.8(1+0.03/12)^12*2

=2060.8(1+0.0025)^24

=2060.8(1.0025)^24

=2060.8(1.0618)

=$2188.157

After three years

A=p(1+r/n)^nt

=2188.157(1+0.03/12)^12*3

=2188.157(1+0.0025)^36

=2188.157(1.0025)^36

=2188.157(1.0941)

=$2394.063

8 0
2 years ago
A local city collects 8% sales tax. If the total purchase was $216.00, then how much was collected for sales tax?
Phantasy [73]
$216 x 0.08 = $17.28.
Therefore $17.28 was collected for sales tax.
4 0
2 years ago
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