Answer:
C. With a p-value less than 0.0001, there is sufficient evidence to reject the null hypothesis and accept the alternative as true.
Step-by-step explanation:
She performed an hypothesis test with the sample of size n=15 that she takes. The t-statistic has a value of 6.661.
The degrees of freedom for this sample size are:
The P-value for a statistic t=6.661 and 14 degrees of freedom is:
With these P-value we know that the effect is significant and the null hypothesis is rejected. There is enough evidence to support the claim that the mean height of Mountain Ash trees is greater than the coastal Douglas Firs.
<h3>
Answer: (C) (14,8)</h3>
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Explanation:
The perimeter of the square is 36, so each side length is 36/4 = 9 units.
Point B is located at (5,17). We move down 9 units to get to (5,8), which is the location of point A. Then we move 9 units to the right to arrive at (14,8) which is point D's location.
Or we could go from B = (5,17) to C = (14,17) and then to D = (14,8). Each time we move 9 units.
Note that: (10x - 61) & (x + 10) are supplementary angles, and (10x-61) & (18y + 5) are vertical angles
10x - 61 + x + 10 = 180
Simplify
11x - 51 = 180
Isolate the x
11x - 51 (+51) = 180 (+51)
11x = 231
Divide 11 from both sides
11x/11 = 231/11
Divide
x = 21
180 = 18y + 5 + x + 10
180 = 18y + 5 + (21) + 10
Simplify
180 = 18y + 36
Subtract 36 from both sides
180 (-36) = 18y + 36 (-36)
144 = 18y
Divide 18 from both sides
144/18 = 18y/18
y = 144/18
y = 8
x = 21, y = 8 are your answers
hope this helps
Draw the picture and label the
width = w
The length of the monitor is six times the quantity of five less than half its width:
length = 6(w/2-5)
length = 3w-30
Area = (length)*(width)
384=(3w-30)*(w)
384=3w^2-30w
Answer:
the dimensions of the monitor in terms of its width is:
384=3w^2-30w
