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2 years ago

What is the completely factored form of the expression 16x2 + 8x + 32?

1 answer:

7 0

<span>8 is a common factor for all coeficients so we factor it out first: 8(2x^2 + x + 4). Now we have to check can we factor the quadratic equasion in the brackets to linear factors. To do that we need to check is the discriminant D=b^2 - 4ac > 0 where a=2, b=1 and c=4. When we insert our numbers, we get: D= -31. We see that D < 0 so 8(2x^2 + x + 4) is the completely factored form.</span>

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Graph the line that represents a proportional relationship between Y And x where the unit rate of change of y with their respect

aksik [14]

Answer:

$y=\frac{3}{8}x$

The graph in the attached figure

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Remember that

The unit rate of change is the same as the slope

In this problem

$m=\frac{3}{8}$

The linear equation is equal to

$y=\frac{3}{8}x$

To graph the line we need two points

we have (0,0) because the line passes through the origin

Determine other point

assume a value of x and calculate the value of y

For x=8

$y=\frac{3}{8}(8)=3$

The other point is (8,3)

Plot the points and join them to draw the line

The graph in the attached figure

3 0

2 years ago

A store sells 8 colors of balloons with at least 28 of each color. How many different combinations of 28 balloons can be chosen?

Len [333]

Answer:

(a) $Selection = 6724520$

(b) $At\ most\ 12 = 6553976$

(c) $At\ most\ 8 = 6066720$

(d) $At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

Step-by-step explanation:

Given

$Colors = 8$

$Balloons = 28$ --- at least

Solving (a): 28 combinations

From the question, we understand that; a combination of 28 is to be selected. Because the order is not important, we make use of combination.

Also, because repetition is allowed; different balloons of the same kind can be selected over and over again.

So:

$n => 28 + 8-1$ $= 35$

$r = 28$

$Selection = ^{35}^C_{28$

$Selection = \frac{35!}{(35 - 28)!28!}$

$Selection = \frac{35!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29*28!}{7!28!}$

$Selection = \frac{35*34*33*32*31*30*29}{7!}$

$Selection = \frac{35*34*33*32*31*30*29}{7*6*5*4*3*2*1}$

$Selection = \frac{33891580800}{5040}$

$Selection = 6724520$

Solving (b): At most 12 red balloons

First, we calculate the ways of selecting at least 13 balloons

Out of the 28 balloons, there are 15 balloons remaining (i.e. 28 - 13)

So:

$n => 15 + 8 -1 = 22$

$r = 15$

Selection of at least 13 =

$At\ least\ 13 = ^{22}C_{15}$

$At\ least\ 13 = \frac{22!}{(22-15)!15!}$

$At\ least\ 13 = \frac{22!}{7!15!}$

$At\ least\ 13 = 170544$

Ways of selecting at most 12 =

$At\ most\ 12 = Total - At\ least\ 13$ --- Complement rule

$At\ most\ 12 = 6724520- 170544$

$At\ most\ 12 = 6553976$

Solving (c): At most 8 blue balloons

First, we calculate the ways of selecting at least 9 balloons

Out of the 28 balloons, there are 19 balloons remaining (i.e. 28 - 9)

So:

$n => 19+ 8 -1 = 26$

$r = 19$

Selection of at least 9 =

$At\ least\ 9 = ^{26}C_{19}$

$At\ least\ 9 = \frac{26!}{(26-19)!19!}$

$At\ least\ 9 = \frac{26!}{7!19!}$

$At\ least\ 9 = 657800$

Ways of selecting at most 8 =

$At\ most\ 8 = Total - At\ least\ 9$ --- Complement rule

$At\ most\ 8 = 6724520- 657800$

$At\ most\ 8 = 6066720$

Solving (d): 12 red and 8 blue balloons

First, we calculate the ways for selecting 13 red balloons and 9 blue balloons

Out of the 28 balloons, there are 6 balloons remaining (i.e. 28 - 13 - 9)

So:

$n =6+6-1 = 11$

$r = 6$

Selection =

$^{11}C_6 = \frac{11!}{(11-6)!6!}$

$^{11}C_6 = \frac{11!}{5!6!}$

$^{11}C_6 = 462$

Using inclusion/exclusion rule of two sets:

$Selection = At\ most\ 12 + At\ most\ 8 - (12\ red\ and\ 8\ blue)$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 170544+ 657800- 462$

$Only\ 12\ red\ and\ only\ 8\ blue\ = 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = Total - Only\ 12\ red\ and\ only\ 8\ blue$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 6724520 - 827882$

$At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638$

3 0

2 years ago

12) -6n – 20 = -2n +4(1 – 3n)<br> What’s the first step

EastWind [94]

Answer:

n = 3

Step-by-step explanation:

-6n - 20 = -2n + 4 (1-3n)

First distribute the 4 (1-3n)

-6n - 20 = -2n + 4 - 12n

Combine like terms on the right side

-6n - 20 = -14n + 4

Get 'n' on one side by adding -6n to both sides

-20 = -8n + 4

Subtract 4 to both sides

-24 = -8n

Divide -8 to both sides

3 = n

4 0

2 years ago

What is the area of this tile 4in 1in

nikitadnepr [17]

Answer:

4 in

Step-by-step explanation:

area is inside you have to multiply

4 times 1 is 4

4 0

2 years ago

Ms. tucker travels through two intersections with traffic lights as she drives to the market. the traffic lights operate indepen

sergij07 [2.7K]

The probability of two independent events occurring one after the another is the product of these probabilities, i.e. $P(red1,red2)=0.22$

We have given that the probability of the first being red and the second not being red is 0.33,

The probability of the first light being red is $P(red1)=0.33+0.22=0.55$ .

And we know that these events are independent, then

$P(red1)*P(red2)=P(red1,red2)$
$0.55*P(red2)=0.22$
$P(red2)=0.4$

4 0

2 years ago