Answer:
$311.74
Step-by-step explanation:
A financial calculator computes the payment amount to be $311.74.
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Your graphing calculator may have the capability to do this. Certainly, such calculators are available in spreadsheet programs and on the web.
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The appropriate formula is the one for the sum of terms of a geometric series.
Sn = a1·((1+r)^n -1)/(r) . . . . . where r is the monthly interest rate (0.005) and n is the number of payments (480). Filling in the given numbers, you have ...
$620827.46 = a1·(1.005^480 -1)/.005 = 1991.4907·a1
Then ...
$620827.46/1991.4907 = a1 ≈ $311.74
Answer:
Yes, it would be statistically significant
Step-by-step explanation:
The information given are;
The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%
Number of jawbreakers in the sample, n = 800
The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = 
=p
The formula for the standard deviation of a proportion is 
Solving for the standard deviation gives;
Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4 in the sample of 800 = 800*0.6 = 480
For statistical significance the difference from the mean = 2×
= 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7
The z-score of 494 jawbreakers is given as follows;
Therefore, the z-score more than 2 × which is significant.
What you put is correct. A’B’C’D’ is what would be shown if you rotate ABCD 90 degrees clockwise
R = a2/a1 = 36/120 = 0.2
a5 = a1 * r^4 = 120 * 0.2^4 = 120 * 0.0016 = 0.192
Hope it helps!
Answer:
or 
Step-by-step explanation:
This is factorable.
The leading coefficient is 1.
Since this is a quadratic all we have to do is find two numbers that multiply to be c and add up to be b to factor the expression that is to the left of the equal sign.
By the way a quadratic expression looks like 
.
So we want to find two numbers that multiply to be -6 and add up to be -1.
Those numbers are -3 and 2 since (-3)(2)=-6 and -3+2=-1.
So the factored form is:
.
Since we have a product is zero then at least one of the factors need to be zero in order for the equation to hold.
So this means we have the following two equations to solve:
or 
First equation we will add 3 on both sides.
Second equation we will subtract 2 on both sides.
or
