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Gwar [14]
2 years ago
14

A college requires all incoming freshmen to live on campus. The college has two female freshman dormitories: Williams and Hillsi

de. For an upcoming school year, there are 800 incoming female freshmen. Which of the following best describes a method of assigning the incoming female freshmen to the two dormitories so that each incoming female freshman has a fair chance of being selected for either dormitory?
Mathematics
1 answer:
Gre4nikov [31]2 years ago
4 0
Slit them in a fair order.
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Deal with these relations on the set of real numbers: R₁ = {(a, b) ∈ R² | a > b}, the "greater than" relation, R₂ = {(a, b) ∈
uranmaximum [27]

Answer:

a) R1ºR1 = R1

b) R1ºR2 = R1

c) R1ºR3 = \{ (a,b) \in R^2 \}

d) R1ºR4 = \{ (a,b) \in R^2 \}

e) R1ºR5 = R1

f) R1ºR6 = \{ (a,b) \in R^2 \}

g) R2ºR3 = \{ (a,b) \in R^2 \}

h) R3ºR3 = R3

Step-by-step explanation:

R1ºR1

(<em>a,c</em>) is in R1ºR1 if there exists <em>b</em> such that (<em>a,b</em>) is in R1 and (<em>b,c</em>) is in R1. This means that a > b, and b > c. That can only happen if a > c. Therefore R1ºR1 = R1

R1ºR2  

This case is similar to the previous one. (<em>a,c</em>) is in R1ºR2 if there exists <em>b</em> such that (<em>a,b</em>) is in R2 and (<em>b,c</em>) is in R1. This means that a ≥ b, and b > c. That can only happen if a > c. Hence R1ºR2 = R1

R1ºR3

(a,c) is in R1ºR3 if there exists b such that a < b and b > c. Independently of which values we use for a and c, there always exist a value of b big enough so that b is bigger than both a and c, fulfilling the conditions. We conclude that any pair of real numbers are related.

R1ºR4

This is similar to the previous one. Independently of the values (a,c) we choose, there is always going to be a value b big enough such that a ≤ b and b > c. As a result any pair of real numbers are related.

R1ºR5

If a and c are related, then there exists b such that (a,b) is in R5 and (b,c) is in R1. Because of how R5 is defined, b must be equal to a. Therefore, (a,c) is in R1. This proves that R1ºR5 = R1

R1ºR6

The relation R6 is less restrictive than the relation R3, if we find 2 numbers, one smaller than the other, in particular we find 2 different numbers. If we had 2 numbers a and c, we can find a number b big enough such that a<b and b >c. In particular, b is different from a, so (a,b) is in R6 and (b,c) is in R1, which implies that (a,c) is in R1ºR6. Since we took 2 arbitrary numbers, then any pair of real numbers are related.

R2ºR3

This is similar to the case R1ºR3, only with the difference that we can take b to be equal to a as long as it is bigger than c. We conclude that any pair of real numbers are related.

R3ºR3

If a and c are real numbers such that there exist b fulfilling the relations a < b and b < c, then necessarily a < c. If a < c, then we can use any number in between as our b. Therefore R3ºR3 = R3

I hope you find this answer useful!

5 0
2 years ago
On a coordinate plane, a curved line with a maximum value of (negative 1, 4) and minimum values of (negative 1.25, negative 16)
In-s [12.5K]

Answer:

1+1=2

Step-by-step explanation:

3 0
1 year ago
Read 2 more answers
In circle Y, what is m∠SZT? 86° 94° 108° 128°
liraira [26]
I'm going to assume that is your shape. 
If that is your shape, this is simple:

First, you need to solve for the angle TZU. The formula for it is:
mTZU= 0.5(arcTU+arcSR)
mTZu= 0.5(72°+100°) = 86°

Vertical angles, as you should know, are congruent. Always. mTZU is a vertical angle to mSZR. This means mSZR is also 86°

Now, the sum of all angles should be 360°. Now you need to know the remaining angles, you can do this by:
360° - 86° - 86° = 188°

Now, last step. Since mSZR is also equal to RZU because they are vertical angles, this means you need to divide 188° by 2. 
188°/2 = 94°

Your answer: m∠SZT = 94°

~Hope this helps!

6 0
1 year ago
Read 2 more answers
(04.01)The Baldwin family walked 4/5 of a mile in 4/9 of an hour. What is their unit rate in miles per hour?
sertanlavr [38]
Hello!

Since we know how much they walked in 4/9 of an hour, we will divide 4/5 by 4/9 to get 4/9 to one.

\frac{4}{5}÷\frac{4}{9}=\frac{36}{20} =  \frac{9}{5}

They went 1 4/5 mph or 1.8 mph.

I hope this helps!
7 0
2 years ago
Read 2 more answers
Ian walks down a sloped path. After 6 minutes, he is 3 m above street level. Write the equation in slope-intercept form of the l
Georgia [21]

Answer:

y=-2/3x+7

Step-by-step explanation:

Since you know the path is parallel to the equation y+-2/3x+12, you already know the slope is -2/3.

It says y is the height above street level, so that is 3. The problem says x is time, which is 6, so all you have to solve for is the y intercept.

3 (y, or the height above street level) = (-2/3) 6 (x, or time) + b (unknown y intercept)

3 = -4 + b

7 = b

So, y = -2/3x + 7

8 0
1 year ago
Read 2 more answers
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