In circle Y, what is m∠SZT? 86° 94° 108° 128°
2 answers:
I'm going to assume that is your shape.
If that is your shape, this is simple:
First, you need to solve for the angle TZU. The formula for it is:
mTZU= 0.5(arcTU+arcSR)
mTZu= 0.5(72°+100°) = 86°
Vertical angles, as you should know, are congruent. Always. mTZU is a vertical angle to mSZR. This means mSZR is also 86°
Now, the sum of all angles should be 360°. Now you need to know the remaining angles, you can do this by:
360° - 86° - 86° = 188°
Now, last step. Since mSZR is also equal to RZU because they are vertical angles, this means you need to divide 188° by 2.
188°/2 = 94°
Your answer: m∠SZT = 94°
~Hope this helps!
If that is your shape, this is simple:
First, you need to solve for the angle TZU. The formula for it is:
mTZU= 0.5(arcTU+arcSR)
mTZu= 0.5(72°+100°) = 86°
Vertical angles, as you should know, are congruent. Always. mTZU is a vertical angle to mSZR. This means mSZR is also 86°
Now, the sum of all angles should be 360°. Now you need to know the remaining angles, you can do this by:
360° - 86° - 86° = 188°
Now, last step. Since mSZR is also equal to RZU because they are vertical angles, this means you need to divide 188° by 2.
188°/2 = 94°
Your answer: m∠SZT = 94°
~Hope this helps!
You might be interested in
Answer: 0.2551
Step-by-step explanation:
Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the actual temperature of the medium, and standard deviation σ.
Significance level :
The critical z-value for 95% confidence : (1)
Since , (where x be any random variable that represents the temperature reading from a thermocouple.)
Then, from (1)
(2)
Also, all readings are within 0.5° of μ,
i.e.
i.e. [From (2)]
i.e.
i.e.
The required standard deviation :