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rodikova [14]
1 year ago
9

Ian walks down a sloped path. After 6 minutes, he is 3 m above street level. Write the equation in slope-intercept form of the l

ine that represents Ian’s height above street level, y, over time x, if he knows the path is parallel to another path with equation y = -2/3x + 12
Mathematics
2 answers:
Georgia [21]1 year ago
8 0

Answer:

y=-2/3x+7

Step-by-step explanation:

Since you know the path is parallel to the equation y+-2/3x+12, you already know the slope is -2/3.

It says y is the height above street level, so that is 3. The problem says x is time, which is 6, so all you have to solve for is the y intercept.

3 (y, or the height above street level) = (-2/3) 6 (x, or time) + b (unknown y intercept)

3 = -4 + b

7 = b

So, y = -2/3x + 7

zubka84 [21]1 year ago
3 0

Answer:

it 5y-4x=(334-444)

Step-by-step explanation:

is the right answer i fu.cking promise bro fkkkkk

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For each exercise draw circle O with radius 12. Then draw radii OA and OB to form an angle with the measure named. Find the leng
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2 years ago
Liz buys 17 identical tickets for £208.25 estimate the cost of one ticket
sergeinik [125]

Answer:

£12.25

Step-by-step explanation:

Using unit rate:

\frac{\text{Price}}{\text{Tickets}}=\frac{208.25}{17}=\frac{208.25/17}{17/17}=\frac{\boxed{12.25}}{1}

£12.25 should be the correct answer.

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Kendall has 45 dolphin stickers, 15 shark stickers, and 20 whale stickers. She wants to put an equal number of stickers into bag
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2 years ago
The two lines, P and Q, are graphed below: Line P is drawn by joining ordered pairs negative 8,15 and 6, negative 12. Line Q is
andreyandreev [35.5K]

Solution:

Keep in mind ,

Equation of line joining two points (a,b) and (p,q) is given by :

     \frac{q-b}{p-a}=\frac{y-b}{x-a}

Equation of line P which is obtained by  joining  (- 8,15) and (6, - 12) is given by:  

\frac{y-15}{x+8}=\frac{-12-15}{6+8}\\\\ 14(y-15)=-27(x+8)\\\\ 14 y -210= -27 x - 216\\\\ 27 x+14 y+6=0

Equation of line Q which is obtained by  joining  (4,16) and (-9, 10) is given by:  

\frac{y-16}{x-4}=\frac{16-10}{4+9}\\\\ 13(y-16)=6(x-4)\\\\ 13 y -208= 6 x - 24\\\\ 6 x-13 y+184=0

Equation of line P and Q are

27 x+14 y+6=0-------(1)× 2

6 x-13 y+184=0-------(2)× 9

54 x + 2 8 y+12=0---(1)

54 x -117 y +1656=0----(2)

(1) - (2)

145 y= 1644

y=11.33,

27 x+14 y+6=0-------(1)×13

6 x-13 y+184=0-------(1)×14

351 x + 182 y + 78=0-----(1)

84 x - 182 y +2576=0----(2)

(1) + (2)

435 x + 2654=0

x = - 6.11

So, solution set is (-6.11, 11.33)

Option (C) is true. (−2, 4), because this point makes both the equations incorrect.


8 0
2 years ago
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