Could it be an Imaginary number?
Since the Venus orbits round the sun, the sun is the center of the circular path of the revolution of the planet, Venus.
Thus, the distance of the planet, Venus fron the sun is given by the distance between the points (0, 0) and (41, 53).
Recall that the distance between two points

and

is given by

Thus, the distance between the points (0, 0) and (41, 53) is given by:

Given that each unit of the plane represents 1 million miles, therefore, the distance from the sun to the Venus is 67 million miles.
First of all, a bit of theory: since the area of a square is given by

where s is the length of the square. So, if we invert this function we have
.
Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

So, the diagonal is the side length, multiplied by the square root of 2.
With that being said, your function could be something like this:
double diagonalFromArea(double area) {
double side = Math.sqrt(area);
double diagonal = side * Math.sqrt(2);
return diagonal;
}
Remember
a²-b²=(a-b)(a+b)
8x²-50y²
2(4x²-25y²)
(2)([2x]²-[5y]²)
2(2x-5y)(2x+5y)