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2 years ago

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The relationship between money earned and hours worked is linear. Joe computes the slope between (4, 30) and (12, 90), then comp

utes the slope between (4, 30) and (10, 75). How do the two slopes compare?

2 answers:

ANEK [815]2 years ago

4 0

Answer:

Its c " the same"

Step-by-step explanation:

I took the quizz on edge.

Guest

1 year ago

perfect explanation

____ [38]2 years ago

3 0

Finding the slope of both coordinates, you'll get 15/2. The slopes are the same

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At the frozen yogurt shop, a machine fills cups with 4 ounces of frozen yogurt before adding the toppings. After the cups are fi

timofeeve [1]

In this question, every cups will be filled with 4 ounces yogurt. That mean, the lowest possible of the cups weight would be 4 ounces. After that the customer can the topping without exceeding 6 ounces of total weight. Since it total weight, that means from the 6 ounces there should be 4 ounces of yogurt. Then the maximum weight is 6 ounces
Minimum weight is 4 ounces and maximum weight is 6 ounces, so the answer would be 4,5,6 or any number between 4-6

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2 years ago

Read 2 more answers

Jerry buys a pack of pencils that cost $3 David buys 4 sets of markers each set of marker also cost 3 what is the total cost of

Marat540 [252]

The total cost of marker is 12

7 0

2 years ago

A fence is guarding off a vegetable garden in the form of a rectangle. It has one side that is 10m greater than the other side.

DanielleElmas [232]

Answer:

The length of the fence needed to surround this garden is 188 meters.

Step-by-step explanation:

Given : A fence is guarding off a vegetable garden in the form of a rectangle. It has one side that is 10 m greater than the other side.

To find : The length of the fence needed to surround this garden if the area of the vegetable garden is 2184 m² ?

Solution :

Let the one side of rectangle be 'x'.

Then the other side is 'x+10'.

The area of the rectangle is 2184 m²,

i.e. $x(x+10)=2184$

$x^2+10x-2184=0$

Solve by middle term split,

$x^2+52x-42x-2184=0$

$x(x+52)-42(x+52)=0$

$(x+52)(x-42)=0$

$x=-52,42$

Reject negative value,

The side of the rectangle is 42 m.

The other side is 42+10=52 m

The perimeter of the rectangle is $P=2(l+b)$

$P=2(42+52)$

$P=2(94)$

$P=188$

Therefore, the length of the fence needed to surround this garden is 188 meter.

5 0

1 year ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

<u>Josh:</u>

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em> $h(t)=0$ <em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

2 years ago

AT&T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $

denis-greek [22]

Given:

Cost of four lines = $125

Cost of each additional line = $15

Jason wants to spend at most $200 per month on cell phone expenses.

To find:

The inequality for the given situation.

Solution:

Let $x$ be the number of additional line.

Cost of one additional line = $15

Cost of $x$ additional line = $\$15x$

Total cost = Fixed cost + Addition cost

= $125+15x$

It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

$125+15x\leq 200$

Therefore, the correct option is C.

8 0

2 years ago